Milling: cutters, operations and indexing
Milling machines and cutters, up vs down milling, feed per tooth and table feed, MRR, machining time with approach, maximum chip thickness, and dividing-head indexing.
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Why it matters
Milling makes flat faces, slots, pockets, keyways, gear teeth and free-form surfaces, and it is the main process on machining centres. Because a milling cutter has many teeth each taking a short, interrupted cut, the feeds, chip thickness and machining time are worked out differently from turning — and dividing-head indexing is still the classic way to space slots and teeth.
Key ideas
Machines. Column-and-knee (horizontal and vertical), universal (table swivels for helical work), bed-type and planer-type (heavy work), and CNC machining centres with automatic tool changers.
Cutters
- Plain (slab) mill — teeth on the periphery, axis parallel to the work surface; for wide flat surfaces on a horizontal machine.
- Side-and-face, staddle and gang mills — several cutters on one arbor to mill faces and steps together.
- Face mill — inserted teeth on the face and periphery, axis perpendicular to the surface; the main tool for flat faces.
- End mill — slots, pockets, shoulders and profiles; ball-nose end mills for 3D surfaces.
- Form cutters (gear cutters, convex/concave), slitting saws, T-slot, Woodruff key and dovetail cutters, fly cutters.
Up (conventional) vs down (climb) milling
- Up milling: cutter rotation opposes the feed at the contact. Chip thickness starts at zero and grows to a maximum; the tooth rubs before it bites, and the cutting force tends to lift the work. Safe on machines with backlash in the feed screw; preferred for scaly or hard-skinned work (the tooth starts under the scale).
- Down milling: rotation is in the direction of feed. The chip starts thick and ends thin, there is no rubbing, the force presses the work onto the table, finish and tool life are better. It needs a rigid machine with a backlash eliminator (ball screws on CNC), otherwise the cutter pulls the table in and can break.
Feed terms. Feed per tooth fz (mm/tooth), feed per revolution fz·Z (mm/rev), and table feed fm = fz·Z·N (mm/min). Feeds on milling machines are set as fm.
Chip thickness in slab milling varies along the arc of contact; its maximum is t_max = 2·fz·√(d/D) (for d ≪ D). This, not fz, governs the load per tooth.
Indexing with a dividing head. The worm-and-wheel ratio is usually 40:1, so 40 crank turns rotate the work once.
- Direct indexing — a plate on the spindle (e.g. 24 holes) for simple divisions.
- Simple (plain) indexing — crank turns = 40/n; the fractional part is taken on a hole circle of the index plate (Brown & Sharpe plates: 15, 16, 17, 18, 19, 20 / 21, 23, 27, 29, 31, 33 / 37, 39, 41, 43, 47, 49 holes).
- Angular indexing — one crank turn = 360°/40 = 9° of work rotation, so crank turns = θ/9° (θ in degrees).
- Differential indexing — for numbers (e.g. many primes above 50) not available by simple indexing; the index plate is driven through change gears so it rotates while cranking.
Formulas
N = 1000·V / (π·D)(cutter speed, rev/min; V in m/min; D cutter diameter in mm)fm = fz·Z·N(table feed, mm/min; Z = number of teeth)MRR = w·d·fm(mm³/min; w width of cut, d depth of cut, mm)- Slab (peripheral) milling approach:
A = √(d·(D − d)); timetm = (L + A + O) / fm - Face milling, full clearance at both ends (cutter centre on the work centre line):
A = O = D/2;tm = (L + D) / fm t_max = 2·fz·√(d/D)(maximum uncut chip thickness, slab milling, mm)- Simple indexing:
crank turns = 40 / n; angular indexing:crank turns = θ / 9°
Worked examples
Example 1 (standard). A 300 mm long, 80 mm wide steel block is slab milled with a 100 mm diameter, 8-tooth HSS cutter at V = 30 m/min, fz = 0.1 mm/tooth, depth d = 4 mm, over-travel 2 mm. Find N, fm, machining time, MRR and t_max.
N = 1000·V/(π·D)= 30 000/(π × 100) = 95.5 rev/min.fm = fz·Z·N= 0.1 × 8 × 95.5 = 76.4 mm/min.A = √(d(D − d))= √(4 × 96) = 19.6 mm.tm = (L + A + O)/fm= (300 + 19.6 + 2)/76.4 = 4.21 min.MRR = w·d·fm= 80 × 4 × 76.4 = 24 450 mm³/min.t_max = 2·fz·√(d/D)= 2 × 0.1 × √0.04 = 0.04 mm — much smaller than fz.
Example 2 (GATE level). (a) A 400 mm long, 100 mm wide face is face milled with a 125 mm diameter, 10-insert face mill (centre on the work centre line) at V = 120 m/min, fz = 0.15 mm, depth 3 mm. Find the time for one pass with full clearance, and the MRR. (b) Using a 40:1 dividing head, find the indexing for 46 equal divisions and for an angle of 7°30′.
N = 120 000/(π × 125)= 305.6 rev/min;fm = 0.15 × 10 × 305.6= 458.4 mm/min.tm = (L + D)/fm= (400 + 125)/458.4 = 1.15 min.MRR = 100 × 3 × 458.4= 137 500 mm³/min (137.5 cm³/min).- Indexing 46: 40/46 = 20/23 → 20 holes on the 23-hole circle per division.
- Angle 7°30′ = 7.5°: 7.5/9 = 5/6 = 15/18 → 15 holes on the 18-hole circle.
Common mistakes
- Writing fm = fz·N (forgetting Z) or treating fz as mm/rev.
- Leaving out the approach distance, which can be a large share of a short cut.
- Using the turning MRR formula; in milling MRR = w·d·fm.
- Saying down milling is always better — it needs a backlash-free feed drive and is poor on scaly castings.
- Indexing with 40/n but choosing a hole circle that is not a multiple of the reduced denominator.
- Taking fz as the chip thickness; in slab milling t_max = 2fz√(d/D) is much smaller.
For GATE PI
- NAT on table feed, MRR and machining time for slab, face and end milling (with approach distance).
- Maximum uncut chip thickness in slab milling; power from specific energy and MRR.
- Simple and angular indexing on a 40:1 dividing head.
- MCQs on up vs down milling, cutter types and their uses.
Quick check
- fz = 0.1 mm, Z = 4, N = 600 rev/min. Table feed?
- D = 50 mm, V = 80 m/min. Cutter speed?
- Simple indexing for 24 divisions?
- Which milling method pushes the work down onto the table?
- Slab milling, D = 100 mm, d = 1 mm: approach distance?
Answers: 1. 240 mm/min. 2. 80 000/(π × 50) ≈ 509 rev/min. 3. 40/24 = 1⅔ turns = 1 turn + 12 holes on an 18-hole circle. 4. Down (climb) milling. 5. √(1 × 99) ≈ 9.95 mm.
Interview questions
All Machining and Machine Tools interview questionsTry answering each one aloud before you open it.
1.What is milling and how does it differ from turning?Concept
Milling is a machining process that involves the use of rotary cutters to remove material from a workpiece. It differs from turning in that milling involves a rotating tool and a stationary workpiece, whereas turning involves a rotating workpiece and a stationary cutting tool.
2.Explain the function of a milling cutter.Concept
A milling cutter is a rotary tool with one or more teeth that is used for machining operations. It is designed to remove material from a workpiece by advancing into the workpiece in a direction at an angle with the axis of the tool. Milling cutters come in various shapes and sizes and are used for different types of milling operations.
3.What are the different types of milling operations?Concept
The different types of milling operations include face milling, where the cutting action occurs at the end corners of the milling cutter; peripheral milling, where the cutting action occurs along the circumference of the cutter; and end milling, which involves the use of an end mill cutter to produce slots, pockets, and contours.
4.Why is climb milling preferred over conventional milling in some cases?Application
In climb (down) milling the cutter rotates in the direction of feed, so each tooth enters at maximum chip thickness and leaves at zero; it does not rub before biting, which gives better finish and longer tool life, and the cutting force presses the work onto the table, which helps thin or lightly clamped parts. However, the force also tends to pull the table along, so climb milling needs a rigid machine with a backlash-free feed drive (ball screw or backlash eliminator). On older machines with backlash, or on castings with hard scale, conventional (up) milling is used instead.
5.What happens if the spindle speed is too high during a milling operation?Application
If the spindle speed is too high during a milling operation, it can lead to excessive heat generation, which may cause thermal damage to the workpiece and reduce tool life. High speeds can also result in poor surface finish and increased vibration, which can affect the accuracy of the machining process.
6.Explain the concept of indexing in milling.Concept
Indexing in milling is a process used to divide the circumference of a workpiece into equal parts. It involves rotating the workpiece by a specific angle between each cut, allowing for the creation of evenly spaced features such as gear teeth or slots. This is typically achieved using a dividing head or an indexing fixture.
7.How does the choice of milling cutter material affect the machining process?Application
The choice of milling cutter material affects the machining process in terms of tool life, cutting speed, and surface finish. Harder materials like carbide can withstand higher cutting speeds and provide longer tool life, but they are more brittle. High-speed steel is tougher and less expensive but wears out faster. The choice depends on the material being machined and the desired outcome.
8.Calculate the spindle speed required for a milling operation if the cutter diameter is 50 mm and the cutting speed is 100 m/min.Numerical
To calculate the spindle speed (N), use the formula: N = (1000 × V) / (π × D), where V is the cutting speed and D is the cutter diameter. Substituting the given values: N = (1000 × 100) / (π × 50) = 636.62 RPM.
9.What is the impact of feed rate on the milling process?Application
The feed rate in milling affects the surface finish, tool life, and machining time. A higher feed rate can increase material removal rate but may lead to a rougher surface finish and reduced tool life due to increased cutting forces. Conversely, a lower feed rate can improve surface finish and tool life but may increase machining time.
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