Drilling, boring and reaming
Twist-drill geometry, drilling machines, boring, reaming and related hole operations; drilling time with point allowance, MRR, chip thickness per lip, power and torque.
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Why it matters
Holes are the most common machined feature — for bolts, dowels, bearings, oil passages. A drill makes the hole quickly but not accurately; boring corrects its position and straightness; reaming gives the final size and finish. Knowing which to use, and how to estimate their time and power, is everyday process-planning work.
Key ideas
Twist drill geometry
- Point angle (2p) — commonly 118° for general work on steel; larger (130°–140°) for hard materials, smaller (90°–100°) for soft or brittle ones.
- Helix angle — the angle of the flutes; it acts as the rake angle at the outer corner of each lip (typically 20°–30°). The effective rake falls towards the centre and becomes strongly negative at the chisel edge.
- Lips (cutting edges) — two, each removing half the feed per revolution.
- Chisel edge — at the web, it does not cut cleanly but extrudes metal; it produces a large part of the thrust force. Web thinning or a pilot hole reduces thrust.
- Lip clearance (about 8°–12°), margin, body clearance and flutes (carry chips out and fluid in).
Drilling machines. Bench and pillar (upright) drills, radial drills (arm swings and head traverses — for large, heavy work), gang and multi-spindle drills (production), deep-hole and gun drills (L/D > 10), and machining/turning centres.
Related hole-making operations
- Boring — enlarging an existing hole with a single-point tool. It corrects hole location, straightness and roundness because the tool follows the spindle axis, not the old hole. Long boring bars (large overhang L/D) are prone to chatter; carbide or damped bars help.
- Reaming — a multi-flute tool removes a small allowance (typically about 0.1–0.5 mm on diameter depending on size) to give accurate size (tolerance around IT7) and good finish. A reamer follows the existing hole, so it cannot correct position or straightness. Run at a lower speed (roughly half to two-thirds of the drilling speed) and a higher feed than drilling.
- Counterboring, countersinking, spot facing — seats for bolt heads and nuts.
- Tapping — cutting internal threads with a tap.
- Trepanning — cutting an annular groove to leave a solid core; for large holes in plates.
- Centre drilling — a short stiff drill to start holes accurately.
Typical sequence for an accurate hole: centre drill → drill (undersize) → bore (to correct position) → ream (to size and finish).
Formulas
N = 1000·V / (π·D)(rev/min; V in m/min at the drill periphery; D drill diameter in mm)MRR = (π·D²/4)·f·N(drilling from solid, mm³/min; f feed in mm/rev)MRR = (π/4)·(D² − d²)·f·N(enlarging, boring or reaming from d to D)A = (D/2)·cot p(length of the drill point, mm; p = half the point angle) — add it to the hole depth for a through hole, plus a small over-travel.tm = (L + A + O) / (f·N)(min)- Uncut chip thickness per lip:
t = (f/2)·sin p; width of cut per lip:w = (D/2) / sin p. - Power:
P = u·MRR(u specific energy from data) and torqueMt = P / ω, withω = 2π·N/60(rad/s). Thrust and torque can also be estimated from empirical data-book formulas.
Worked examples
Example 1 (standard). A 20 mm hole is drilled through a 40 mm plate with an HSS drill (point angle 118°) at V = 25 m/min and f = 0.25 mm/rev. Allow 2 mm over-travel. Find N, the drilling time and the MRR.
N = 1000·V/(π·D)= 25 000/(π × 20) = 398 rev/min.- Point length
A = (D/2)·cot p= 10 × cot 59° = 10 × 0.6009 = 6.01 mm. tm = (L + A + O)/(f·N)= (40 + 6.01 + 2)/(0.25 × 397.9) = 48.01/99.47 = 0.483 min ≈ 29 s.MRR = (π·D²/4)·f·N= 314.16 × 0.25 × 397.9 = 31 250 mm³/min.
Example 2 (GATE level). A 20 mm drill (point angle 118°) cuts steel at f = 0.2 mm/rev and N = 400 rev/min. The specific cutting energy is 3 J/mm³ (given). (a) Find the uncut chip thickness per lip, the power and the torque for drilling from solid. (b) Find the power if the hole is instead enlarged from a 10 mm pilot hole at the same feed and speed.
t = (f/2)·sin p= 0.1 × sin 59° = 0.0857 mm.MRR = (π × 20²/4) × 0.2 × 400= 314.16 × 80 = 25 133 mm³/min = 418.9 mm³/s.P = u·MRR= 3 × 418.9 = 1257 W.- ω = 2π × 400/60 = 41.89 rad/s →
Mt = P/ω= 1257/41.89 = 30.0 N·m. - Enlarging:
MRR = (π/4)(20² − 10²) × 0.2 × 400= 235.6 × 80 = 18 850 mm³/min = 314.2 mm³/s →P = 3 × 314.2= 943 W. The pilot hole removes the chisel-edge region, so the thrust force drops far more than the 25 % fall in power suggests.
Common mistakes
- Forgetting the drill-point length when timing a through hole.
- Using the full feed per lip; each of the two lips takes f/2.
- Using D² − d² with radii instead of diameters (or forgetting the π/4).
- Expecting a reamer to straighten a hole — only boring corrects location and straightness.
- Reaming at drilling speed; reamers need lower speed and adequate allowance (too little allowance makes them rub and glaze).
- Converting N to ω without the 2π/60 factor when finding torque.
For GATE PI
- NAT on drilling/boring/reaming time including point length, MRR from solid and when enlarging, power and torque from specific energy.
- Chip thickness per lip and the role of point angle.
- MCQs on drill geometry (helix angle as rake, chisel edge and thrust), the boring vs reaming distinction, and hole-making sequences.
Quick check
- Drill 10 mm, V = 25 m/min. Spindle speed?
- Which feature of a twist drill produces most of the thrust?
- Can reaming correct the position of a hole?
- Feed 0.3 mm/rev, point angle 118°: uncut chip thickness per lip?
- MRR when enlarging a 15 mm hole to 20 mm at f = 0.1 mm/rev, N = 600 rev/min?
Answers: 1. 25 000/(π × 10) ≈ 796 rev/min. 2. The chisel edge. 3. No — boring does that; reaming only sizes and finishes. 4. 0.15 × sin 59° = 0.129 mm. 5. (π/4)(400 − 225) × 0.1 × 600 = 8247 mm³/min.
Interview questions
All Machining and Machine Tools interview questionsTry answering each one aloud before you open it.
1.What is drilling in the context of machining?Concept
Drilling is a machining process used to create round holes in a workpiece. It involves the use of a drill bit, which is a rotary cutting tool, to cut away material and form a cylindrical hole. The process is typically performed using a drill press or a lathe, and it is one of the most common machining operations.
2.Explain the difference between boring and reaming.Concept
Boring and reaming are both machining processes used to refine holes, but they serve different purposes. Boring is used to enlarge an existing hole and improve its accuracy, often performed after drilling. Reaming, on the other hand, is used to achieve a high-precision finish and exact dimensions on an already drilled or bored hole. Reaming removes a small amount of material to smooth the surface and ensure the hole is of the correct size.
3.Why is coolant used during drilling operations?Application
Coolant is used during drilling operations to reduce the heat generated by friction between the drill bit and the workpiece. This helps to prolong the life of the drill bit, improve the quality of the hole, and prevent damage to the workpiece. Coolant also helps to remove chips from the cutting area, reducing the risk of clogging and ensuring a smoother drilling process.
4.What happens if a drill bit is not properly aligned with the workpiece?Application
If a drill bit is not properly aligned with the workpiece, it can lead to several issues. The hole may be off-center or angled, resulting in inaccurate dimensions. Misalignment can also cause excessive wear on the drill bit, increase the risk of breakage, and produce a poor surface finish. Proper alignment is crucial for achieving precision and maintaining tool life.
5.How does the material of a workpiece affect the choice of drill bit?Application
The material of a workpiece affects the choice of drill bit in terms of hardness, toughness, and thermal properties. For softer materials like aluminum, high-speed steel (HSS) drill bits are often sufficient. For harder materials like stainless steel, carbide-tipped or cobalt drill bits may be necessary to withstand the increased wear and heat. The drill bit material must be chosen to match the workpiece material to ensure efficient cutting and tool longevity.
6.What is the purpose of a pilot hole in drilling?Application
A pilot hole is a small, preliminary hole drilled before the final hole. Its purpose is to guide the larger drill bit, ensuring accuracy and reducing the risk of the bit wandering off course. Pilot holes are especially useful when drilling large or deep holes, as they help to maintain alignment and reduce the amount of material the larger bit must remove, making the process more efficient.
7.Explain the term 'chatter' in the context of boring operations.Concept
Chatter is a self-excited vibration between tool and work that leaves a regular wavy pattern on the bore, spoils size and finish and can chip the tool. Boring is especially prone because the boring bar is a cantilever whose stiffness falls with the cube of its overhang, so a large length-to-diameter ratio invites chatter. Remedies are the shortest, stiffest bar possible (carbide or tuned/damped bars for L/D above about 4–6), a sharp positive-rake tool with a small nose radius to reduce radial force, and adjusting speed and depth to move out of the unstable range.
8.Calculate the spindle speed required for drilling a 10 mm diameter hole in a mild steel workpiece using a high-speed steel drill bit. Assume a cutting speed of 25 m/min.Numerical
To calculate the spindle speed (N) in revolutions per minute (RPM), use the formula: N = (1000 × V) / (π × D), where V is the cutting speed in meters per minute and D is the diameter in millimeters. Substituting the given values: N = (1000 × 25) / (π × 10) ≈ 796 RPM.
9.What are the potential consequences of using an incorrect reamer size?Application
Using an incorrect reamer size can lead to several issues. If the reamer is too large, it may remove too much material, resulting in an oversized hole that does not meet specifications. If it is too small, it may not adequately finish the hole, leaving it undersized or with a poor surface finish. Both scenarios can lead to assembly problems and may require rework or replacement of the part.
10.A reamer is used to finish a hole with a diameter of 20 mm. If the reamer removes 0.5 mm of material in diameter, what was the initial diameter of the hole before reaming?Numerical
The initial diameter of the hole before reaming can be calculated by subtracting the material removed by the reamer from the final diameter. Initial diameter = Final diameter - Material removed = 20 mm - 0.5 mm = 19.5 mm.
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