Interconnection of two-port networks
Cascade, series, parallel and hybrid interconnections of two-ports, the port condition, elementary ABCD blocks and terminated cascades.
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Why it matters
Real systems are built from blocks: a sensor, a cable, a filter section, an amplifier and a feedback network. If you know each block's two-port parameters, the interconnection rules give the parameters of the whole chain directly, without re-solving the full circuit. Ladder filters, multi-section attenuators, bridged-T notch filters and feedback amplifiers are all analysed this way.
Key ideas
Five standard interconnections. In each case, pick the parameter set in which the quantities that are shared by both networks are the independent variables. The dependent quantities then add.
- Cascade (tandem). The output port of network a feeds the input port of network b, so V2a = V1b and −I2a = I1b. The ABCD matrices multiply in order:
[T] = [Ta]·[Tb]. Order matters, since matrix multiplication is not commutative. - Series–series. Both input ports are in series and both output ports are in series. The port currents are common and the voltages add, so
[Z] = [Za] + [Zb]. This models current-sensing (series) feedback at both ports. - Parallel–parallel. Both input ports are in parallel and both output ports are in parallel. The port voltages are common and the currents add, so
[Y] = [Ya] + [Yb]. Examples are a bridged-T, a twin-T, and shunt–shunt feedback. - Series–parallel. Inputs in series, outputs in parallel:
[h] = [ha] + [hb]. This models voltage-series feedback amplifiers. - Parallel–series. Inputs in parallel, outputs in series:
[g] = [ga] + [gb].
Validity: the port condition (Brune's test). The addition rules hold only if, after connection, each network still has equal and opposite currents at the two terminals of each port. Interconnecting can create circulating currents that violate this.
- Three-terminal networks (common ground between ports) connected in parallel–parallel or cascade always satisfy it.
- Series connections of three-terminal networks need care. One network's ground can short part of the other.
- When in doubt, insert an ideal 1:1 isolating transformer at a port; that always restores the port condition.
Cascade building blocks.
- Series impedance Z:
[[1, Z], [0, 1]]. - Shunt admittance Y:
[[1, 0], [Y, 1]]. - Ideal transformer N1:N2 = n:
[[n, 0], [0, 1/n]].
Any ladder network is the product of these matrices, taken from input to output.
Terminated cascade. With load ZL at the output:
Zin = (A·ZL + B)/(C·ZL + D)V2/V1 = ZL/(A·ZL + B)- With the output open,
V1/V2 = A. - With the output shorted,
Zin = B/D.
Identical networks. Two identical reciprocal networks in parallel–parallel give Y = 2·Ya, so the overall Z matrix is half of Za. In series–series, Z = 2·Za.
Formulas
- Cascade:
[A B; C D] = [Aa Ba; Ca Da]·[Ab Bb; Cb Db] - Series–series:
[Z] = [Za] + [Zb](Ω) - Parallel–parallel:
[Y] = [Ya] + [Yb](S) - Series–parallel:
[h] = [ha] + [hb]. Parallel–series:[g] = [ga] + [gb]. - Series element:
T = [[1, Z], [0, 1]]. Shunt element:T = [[1, 0], [Y, 1]]. - Terminated:
Zin = (A·ZL + B)/(C·ZL + D),V2/V1 = ZL/(A·ZL + B). - Reciprocity is preserved: if each block has AD − BC = 1, so does the cascade.
Worked examples
Example 1 (standard): cascade of two L-sections. Given: each section is a 2 Ω series resistor followed by a 0.5 S shunt conductance. Two identical sections are cascaded and loaded with RL = 4 Ω. Find the overall ABCD matrix, Zin and V2/V1.
- One section:
[[1, 2], [0, 1]]·[[1, 0], [0.5, 1]] = [[2, 2], [0.5, 1]]. - Two sections:
[[2, 2], [0.5, 1]]·[[2, 2], [0.5, 1]] = [[2·2 + 2·0.5, 2·2 + 2·1], [0.5·2 + 1·0.5, 0.5·2 + 1·1]] = [[5, 6], [1.5, 2]]. - Check:
AD − BC = 10 − 9 = 1✓ (reciprocal). - Input impedance:
Zin = (5·4 + 6)/(1.5·4 + 2) = 26/8 = 3.25 Ω. - Voltage gain:
V2/V1 = 4/(5·4 + 6) = 4/26 = 0.154.
Answer: T = [[5, 6 Ω], [1.5 S, 2]], Zin = 3.25 Ω, V2/V1 = 0.154.
Example 2 (GATE level): a bridged-T as a parallel–parallel connection. Given: a T network with series arms 2 Ω and 2 Ω and a shunt arm of 1 Ω, bridged by a 2 Ω resistor connected directly from input to output (common ground). Find the Y parameters, z11 and the open-circuit voltage ratio V2/V1.
- T network:
Za = [[3, 1], [1, 3]]withΔZ = 8, soYa = [[0.375, −0.125], [−0.125, 0.375]] S. - Bridging resistor (series element between the top terminals):
Yb = [[0.5, −0.5], [−0.5, 0.5]] S. - Both are three-terminal networks with a common ground, so the port condition holds and
Y = Ya + Yb = [[0.875, −0.625], [−0.625, 0.875]] S. ΔY = 0.875² − 0.625² = 0.375, soz11 = y22/ΔY = 0.875/0.375 = 2.333 Ω.- Open-circuit voltage ratio:
V2/V1 = −y21/y22 = 0.625/0.875 = 0.714. - Direct check: with the output open, the input sees
(2 ∥ (2 + 2)) + 1 = 1.333 + 1 = 2.333 Ω✓.
Answer: Y = [[0.875, −0.625], [−0.625, 0.875]] S, z11 = 2.33 Ω, V2/V1 = 0.714.
Common mistakes
- Adding ABCD matrices for a cascade, or multiplying them in the wrong order.
- Adding Z matrices for a parallel connection (add Y), or Y matrices for a series connection (add Z).
- Ignoring the port condition. Series connections of grounded networks often violate it.
- Treating "series connection" of two-ports as a cascade. They are different.
- Forgetting the sign convention for I2 when chaining ABCD (−I2a = I1b).
For GATE IN
Typical questions: the overall ABCD of a cascade of simple sections; Z of a series–series or Y of a parallel–parallel combination; Zin or the gain of a terminated cascade; recognising which parameter set adds for a given feedback topology; checking reciprocity of the result. Practise the elementary series, shunt and transformer matrices, since most cascade questions reduce to multiplying two or three of them.
Quick check
- Which parameters add when two two-ports are connected in parallel at both ports?
- What is the ABCD matrix of a single shunt admittance Y?
- Two identical networks with Z = [[4, 2], [2, 4]] Ω are connected series–series. What is the overall Z?
- A cascade has A = 5. What is V1/V2 with the output open?
Answers: 1. Y parameters. 2. [[1, 0], [Y, 1]]. 3. [[8, 4], [4, 8]] Ω. 4. 5.
Interview questions
All Electrical Circuits interview questionsTry answering each one aloud before you open it.
1.How do you interconnect two two-port networks in series, and how are the overall parameters found?Concept
In a series–series connection the two input ports are connected in series and the two output ports are connected in series. Both networks then carry the same port currents, and their port voltages add, so the overall Z matrix is Za + Zb. This holds only if the port condition still holds after connection (Brune's test), which can fail for grounded three-terminal networks; an ideal isolating transformer fixes that. Connecting the output of one network to the input of the next is a cascade, not a series connection; for a cascade you multiply ABCD matrices.
2.Why are T (ABCD) parameters preferred for cascading two-port networks?Application
ABCD parameters express the input quantities (V1, I1) in terms of the output quantities (V2, −I2). In a cascade, the output of one stage is exactly the input of the next, so the overall matrix is simply the product T = Ta·Tb·Tc… taken in order from input to output. Elementary series, shunt and transformer blocks have very simple ABCD matrices, so any ladder can be built up by multiplication. Other parameter sets would need conversion at every stage.
3.What happens to the overall parameters if two identical two-port networks are connected in parallel at both ports?Application
In a parallel–parallel connection the port voltages are shared and the currents add, so Y = Ya + Ya = 2Ya, provided the port condition is satisfied (it is for three-terminal networks with a common ground). The overall Z matrix is the inverse of 2Ya, which is Za/2. So every open-circuit impedance, including the input impedance with the output open, is halved.
4.What is the impact on the input impedance of a two-port network if the load impedance is changed?Application
For a two-port with load ZL, Zin = z11 − z12·z21/(z22 + ZL), or (A·ZL + B)/(C·ZL + D) in ABCD form. So the input impedance depends on the load through the transfer terms z12·z21. If the network is unilateral (z12 = 0, like an ideal buffer amplifier), Zin = z11 regardless of load; this isolation is exactly what buffer stages provide in instrumentation. For a reciprocal passive network, changing ZL always changes Zin unless z12 = 0.
5.Calculate the overall Z-parameters for two two-port networks with Z-parameters Z1 = [[2, 1], [1, 2]] and Z2 = [[3, 2], [2, 3]] connected in series.Numerical
To find the overall Z-parameters for two networks connected in series, you add the corresponding Z-parameters of the two networks. Therefore, Z_total = Z1 + Z2 = [[2+3, 1+2], [1+2, 2+3]] = [[5, 3], [3, 5]].
6.If a two-port network has Y-parameters Y = [[0.5, −0.2], [−0.2, 0.5]] S, what are the Z-parameters?Numerical
Z is the matrix inverse of Y. ΔY = 0.5 × 0.5 − (−0.2)(−0.2) = 0.21 S². So z11 = y22/ΔY = 0.5/0.21 = 2.381 Ω, z22 = y11/ΔY = 2.381 Ω, and z12 = z21 = −y12/ΔY = 0.2/0.21 = 0.952 Ω. The network is reciprocal and symmetric.
7.Describe a practical application where two-port network analysis is essential.Application
Two-port network analysis is essential in the design and analysis of amplifiers, especially in RF and microwave engineering. It helps in understanding how signals are transmitted and transformed through the amplifier, allowing engineers to optimize performance parameters like gain, input/output impedance, and stability.
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