TTT and CCT diagrams

Isothermal (TTT) and continuous-cooling (CCT) diagrams for steel: pearlite, bainite and martensite, the nose and Ms, critical cooling rate, effect of alloying, and Avrami kinetics.

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Why it matters

The iron–carbon diagram says what forms after very slow cooling, but real parts are quenched in water or oil, air-cooled or held in salt baths. TTT and CCT diagrams add the missing variable, time, and so tell you whether a gear will become martensite, bainite or pearlite, how fast it must be quenched, and why alloy steels harden in oil when plain carbon steels need water.

Key ideas

Transformation kinetics. Austenite cooled below A1 does not transform instantly: it needs nucleation and diffusion-controlled growth. Just below A1 the driving force is small, so nucleation is slow; at low temperature diffusion is slow. The fastest transformation is in between, which gives the C-shaped curves.

TTT (isothermal transformation) diagram. Built by austenitising small samples, quenching them rapidly to a fixed temperature, holding for various times and examining the structure. It plots temperature against log time and shows:

  • the start curve (about 1 % transformed) and the finish curve (about 99 %), and often the 50 % curve;
  • the nose: the temperature (about 540 °C for eutectoid plain carbon steel) at which transformation starts soonest (under a second for plain eutectoid steel);
  • the horizontal Ms (martensite start, about 220 °C for eutectoid steel) and Mf (martensite finish) lines. For hypoeutectoid and hypereutectoid steels an extra curve shows proeutectoid ferrite or cementite forming first above the nose.

Products of austenite (eutectoid steel).

  • Coarse pearlite (just below 727 °C down to about 650 °C): widely spaced lamellae, softer.
  • Fine pearlite (about 650–540 °C): thinner lamellae, harder and stronger, because the interlamellar spacing is smaller.
  • Upper bainite (about 540–350 °C): feathery; ferrite laths with cementite between them.
  • Lower bainite (about 350 °C to Ms): acicular plates with fine carbides inside; strong and tough.
  • Martensite (below Ms): forms only when austenite is cooled so fast that diffusion is suppressed. The transformation is diffusionless and athermal — the amount depends on how far below Ms the steel is cooled, not on time. Martensite is a supersaturated body-centred tetragonal (BCT) solution of carbon; its hardness rises steeply with carbon content up to about 0.6 % C. It is hard and brittle and must be tempered.
  • Retained austenite: if Mf is below room temperature (high-carbon and alloy steels), some austenite survives quenching; sub-zero treatment converts it.

Reading a path on a TTT diagram. Only isothermal paths (quench to a temperature, hold, then cool) can be read strictly. Example: quench to 600 °C and hold until the finish line → fine pearlite. Quench to 300 °C, hold → lower bainite. Quench straight below Mf → martensite. Quench to 600 °C, hold for half the transformation time, then quench to room temperature → about 50 % fine pearlite and 50 % martensite.

CCT (continuous cooling transformation) diagram. Real parts cool continuously. On a CCT diagram the curves lie lower and further to the right than on the TTT diagram for the same steel (it takes longer to reach a given transformed fraction when temperature keeps dropping). In plain carbon eutectoid steel, bainite does not form during continuous cooling. Cooling curves are superimposed to read the product, and the final hardness is often printed at the end of each curve.

Critical cooling rate. The slowest cooling rate whose curve just misses the nose of the CCT start curve, producing 100 % martensite. A plain carbon steel needs roughly 100–200 °C/s (water quench); alloy steels need far less.

What shifts the curves.

  • Alloying elements (except cobalt) — Cr, Mo, Mn, Ni — and higher carbon (up to eutectoid) shift the C-curves to the right, lowering the critical cooling rate and raising hardenability.
  • A coarser austenite grain size also shifts them right (fewer nucleation sites), but at the cost of toughness.
  • Carbon and most alloying elements lower Ms and Mf.

Avrami kinetics. The fraction transformed at a fixed temperature follows an S-shaped curve against time described by the Avrami equation. Because time is plotted logarithmically, the 50 % time is not the arithmetic mean of the start and finish times.

Formulas

y = 1 − exp(−k·tⁿ) Avrami equation: y = fraction transformed (0–1), t = time (s), k = rate constant (s⁻ⁿ), n = Avrami exponent (typically 1–4); both from experiment at the given temperature.

t_y = [ −ln(1 − y) / k ]^(1/n) Time to reach fraction y.

t₀.₅ = (ln 2 / k)^(1/n) and rate = 1 / t₀.₅ Half-transformation time and the usual definition of transformation rate.

CR_crit ≈ (T_γ − T_nose) / t_nose A rough estimate of the critical cooling rate from the austenitising temperature T_γ (°C) to the nose (T_nose in °C, t_nose in s). It overestimates slightly because it uses the TTT nose; use the CCT diagram when available.

Worked examples

Example 1 (standard): Avrami kinetics. Given: at 600 °C a steel transforms with n = 2.5 and is 50 % transformed after 20 s.

  1. k = ln 2 / t₀.₅ⁿ = 0.6931 / 20^2.5 = 0.6931 / 1788.9 = 3.87 × 10⁻⁴ s^(−2.5).
  2. Time to 95 %: t = [−ln 0.05 / k]^(1/2.5) = [2.996 / 3.87 × 10⁻⁴]^0.4 = 35.9 s.
  3. Fraction after 30 s: y = 1 − exp(−3.87 × 10⁻⁴ × 30^2.5) = 1 − exp(−1.910) = 0.85.

Example 2 (GATE level): finding t₀.₅ and the critical cooling rate. (a) At one temperature transformation is 1 % complete at 10 s and 99 % complete at 100 s. Find n and the 50 % time.

  1. ln[−ln(1 − y)] = ln k + n·ln t. For y = 0.01: ln(0.01005) = −4.600; for y = 0.99: ln(4.605) = 1.527.
  2. n = (1.527 − (−4.600)) / (ln 100 − ln 10) = 6.127 / 2.303 = 2.66.
  3. ln k = −4.600 − 2.66 × 2.303 = −10.73.
  4. t₀.₅ = (ln 2 / k)^(1/n) = exp[(ln 0.6931 + 10.73) / 2.66] = 49 s — not the average 55 s. (b) A steel is austenitised at 850 °C; the nose of its transformation-start curve is at 550 °C and 1.5 s. Rough critical cooling rate = (850 − 550)/1.5 = 200 °C/s, which needs a vigorous water quench.

Common mistakes

  • Reading a continuous cooling curve directly on a TTT diagram as if it were exact.
  • Thinking martensite forms with time at a fixed temperature; its amount depends on temperature below Ms.
  • Calling martensite a phase on the equilibrium diagram; it is metastable and does not appear there.
  • Averaging start and finish times on a log-time diagram.
  • Saying alloying moves the curves left; it moves them right (more hardenable).
  • Expecting bainite from continuous cooling of plain carbon eutectoid steel; it is obtained by isothermal holding (austempering).

For GATE PI

Expect questions that trace a time–temperature path on a TTT diagram and ask for the final microstructure, define the nose, Ms and critical cooling rate, compare TTT and CCT, and ask how alloying or carbon shifts the curves. Numericals use the Avrami equation (time for a given fraction, n or k from two data points) or a simple critical-cooling-rate estimate.

Quick check

  1. What does the nose of a TTT curve represent?
  2. A eutectoid steel is quenched to 400 °C and held until transformation ends. What forms?
  3. Does adding chromium raise or lower the critical cooling rate?
  4. Why is martensite called an athermal transformation?
  5. With n = 2 and t₀.₅ = 10 s, what fraction is transformed at 20 s?

Answers: 1. The temperature at which austenite starts transforming in the shortest time; 2. Upper bainite; 3. Lowers it; 4. The amount formed depends on how far below Ms the steel is cooled, not on holding time; 5. 1 − 2^(−4) = 0.9375.

Try answering each one aloud before you open it.

  1. 1.What is a TTT diagram and what does it represent?Concept

    A TTT (Time-Temperature-Transformation) diagram is a graphical representation that shows the relationship between temperature and time for the transformation of austenite into other phases like pearlite, bainite, and martensite in steel. It helps in understanding the kinetics of phase transformations and is used to predict the microstructure of steel after heat treatment.

  2. 2.Explain the difference between TTT and CCT diagrams.Concept

    TTT diagrams (Time-Temperature-Transformation) are used for isothermal transformations, meaning the temperature is held constant during the transformation. CCT diagrams (Continuous Cooling Transformation) are used for continuous cooling processes, where the temperature changes over time. CCT diagrams are more practical for industrial applications as they represent real-world cooling conditions.

  3. 3.Why are CCT diagrams more commonly used in industrial applications than TTT diagrams?Application

    CCT diagrams are more commonly used in industrial applications because they represent the continuous cooling conditions that occur in real-world processes, such as welding or casting. Unlike TTT diagrams, which assume constant temperature, CCT diagrams provide a more accurate prediction of the microstructure and properties of the material after cooling.

  4. 4.What happens if steel is cooled too quickly according to a TTT diagram?Application

    If steel is cooled too quickly, it may bypass the nose of the TTT curve, leading to the formation of martensite instead of pearlite or bainite. Martensite is a hard and brittle phase, which can increase the hardness of the steel but also make it more susceptible to cracking.

  5. 5.How can TTT diagrams be used to design heat treatment processes?Application

    TTT diagrams can be used to design heat treatment processes by selecting the appropriate temperature and time to achieve the desired microstructure. By understanding the transformation kinetics, engineers can control the cooling rate to form specific phases like pearlite, bainite, or martensite, optimizing the mechanical properties of the steel.

  6. 6.What is the significance of the 'nose' of a TTT diagram?Concept

    The nose is the temperature (about 540 °C for a plain eutectoid steel) at which the transformation-start curve reaches its shortest time, because the driving force for transformation and the diffusion rate are best balanced there. To get martensite, the steel must be cooled past the nose before transformation can start, so the nose sets the critical cooling rate. Alloying elements push the nose to longer times, which is why alloy steels can be hardened with a slower oil quench.

  7. 7.Explain how bainite forms in steel and its representation on a TTT diagram.Concept

    Bainite forms when austenite transforms between the nose (about 540 °C) and Ms (about 220 °C for eutectoid steel), where carbon can diffuse only short distances, so ferrite forms as laths or plates with cementite between them (upper bainite) or as fine carbides inside the plates (lower bainite). On a TTT diagram it occupies the lower part of the C-curves below the nose. In practice it is obtained by isothermal holding (austempering) rather than continuous cooling, and lower bainite combines high strength with better toughness than tempered martensite of the same hardness.

  8. 8.At 600 °C austenite starts transforming (1 %) at 10 s and finishes (99 %) at 100 s. Estimate the time for 50 % transformation.Numerical

    The transformation follows the Avrami equation y = 1 − exp(−k·tⁿ), so you cannot simply average the times. Writing ln[−ln(1 − y)] = ln k + n·ln t for the two points gives n = (1.527 + 4.600)/ln 10 = 2.66 and ln k = −10.73. Then t₅₀ = (ln 2 / k)^(1/n) ≈ 49 s, not 55 s. A quick approximation on a log-time axis is the geometric mean, √(10 × 100) ≈ 32 s, which shows how misleading arithmetic averaging is.

  9. 9.If a steel alloy has a critical cooling rate of 5°C/s to form martensite, what happens if it is cooled at 3°C/s?Application

    If the steel alloy is cooled at 3°C/s, which is slower than the critical cooling rate of 5°C/s, it will not form martensite. Instead, it will likely form pearlite or bainite, depending on the specific TTT or CCT diagram of the alloy. This results in a softer and more ductile microstructure.

  10. 10.A steel is austenitised at 800 °C and the nose of its TTT diagram is at 550 °C and 10 s. Estimate the cooling rate needed to avoid pearlite.Numerical

    The steel must cool from 800 °C past the nose temperature of 550 °C before transformation can start there, i.e. a drop of 250 °C in less than about 10 s. The rough critical cooling rate is therefore 250/10 = 25 °C/s. This TTT-based figure is only an estimate: during continuous cooling the start curve lies lower and to the right (CCT diagram), so the true critical rate is somewhat lower, and the CCT diagram should be used when available.

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