Hardness, impact, fatigue and creep testing
Brinell, Vickers, Rockwell and Knoop hardness; Charpy and Izod impact energy and the ductile-to-brittle transition; fatigue (S–N curve, Goodman, Basquin) and creep (stages, Larson–Miller).
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Why it matters
Most service failures are not simple overloads: shafts break by fatigue after millions of cycles, boiler tubes and turbine blades fail by creep, and steel structures crack suddenly in cold weather. Hardness checks heat treatment on the shop floor in seconds, impact tests screen steels for brittle fracture, and fatigue and creep data set the life of rotating and high-temperature parts.
Key ideas
Hardness is resistance to localised plastic deformation (indentation). It correlates with tensile strength, so it is the quickest check that a heat treatment worked.
- Brinell (HB / HBW): a hardened steel or tungsten-carbide ball (usually D = 10 mm) pressed with a large load (3000 kgf for steels, 500 kgf for soft metals) for 10–15 s; the indentation diameter d is measured with a microscope. Large indent averages out coarse structures such as cast iron; not for very hard or thin parts.
- Vickers (HV): a square-based diamond pyramid with 136° between opposite faces; the mean diagonal d is measured. One continuous scale from soft to very hard materials; micro-Vickers measures individual phases and case-depth profiles.
- Knoop (HK): an elongated diamond pyramid giving a shallow indent, for thin layers and brittle materials.
- Rockwell (HR): measures depth of penetration under a major load after a minor (preload) load; the number is read directly on a dial. HRC uses a 120° diamond cone with 150 kgf total load (hardened steel); HRB uses a 1/16 in steel ball with 100 kgf (soft steel, brass). Fast and needs no optical measurement, so it suits production checks; it leaves only a small dent.
- Shore scleroscope / rebound: height of rebound of a diamond-tipped hammer; portable, for large parts. For steels, UTS (MPa) ≈ 3.45 × HB is a useful empirical rule.
Impact testing measures the energy absorbed in fracturing a notched specimen at a high strain rate, a measure of notch toughness.
- Charpy: specimen simply supported as a beam, notch facing away from the pendulum, struck at mid-span.
- Izod: specimen held vertically as a cantilever, notch facing the striker.
- Energy absorbed = loss of potential energy of the pendulum = m·g·(h1 − h2).
- Ductile-to-brittle transition (DBTT): BCC metals (ferritic steels) absorb much energy at high temperature (ductile, fibrous fracture) and little at low temperature (brittle cleavage, shiny facets). FCC metals (Al, Cu, austenitic stainless steel) show no transition, which is why they are used for cryogenic service. Fine grain size and low carbon lower the DBTT.
Fatigue is failure under fluctuating stress whose peak is below the yield strength. A crack initiates at a stress raiser (notch, scratch, inclusion, weld toe), grows a little each cycle (leaving beach marks and striations) and finally the remaining section breaks suddenly.
- The S–N (Wöhler) curve plots stress amplitude against cycles to failure on a log scale. Steels and titanium show an endurance limit (about 0.5 × UTS for steels up to UTS ≈ 1400 MPa) below which life is effectively infinite; aluminium and copper alloys do not, so a fatigue strength at 10⁷ or 10⁸ cycles is quoted.
- A tensile mean stress shortens life; the Goodman line corrects for it.
- Improve fatigue life by smooth surfaces, generous fillets, shot peening, carburising or nitriding (all add compressive residual stress at the surface), and by avoiding corrosion (corrosion fatigue removes the endurance limit).
Creep is time-dependent plastic deformation under constant load, significant above about 0.4 of the absolute melting temperature (0.3–0.4 Tm for metals; lead creeps at room temperature).
- Creep curve: instantaneous strain on loading, then primary creep (decreasing rate, strain hardening dominates), secondary or steady-state creep (constant minimum rate, hardening balanced by recovery — the design parameter), and tertiary creep (accelerating rate from necking, voids and grain-boundary cavities) ending in rupture.
- Creep resistance improves with high melting point, coarse grains or single crystals (fewer grain boundaries for sliding), solid-solution and stable precipitate strengthening (nickel superalloys).
- Life at service conditions is extrapolated from short tests at higher temperature using the Larson–Miller parameter.
Formulas
HB = 2F / (π·D·(D − √(D² − d²)))
F = load (kgf); D = ball diameter (mm); d = indentation diameter (mm). HB in kgf/mm², quoted as a number. If F is in newtons, multiply by 0.102.
HV = 1.8544·F / d²
F = load (kgf); d = mean diagonal (mm).
E_abs = m·g·(h1 − h2)
Charpy/Izod energy absorbed (J); m = hammer mass (kg); h1, h2 = heights of the hammer's centre before release and after the swing-through (m).
σm = (σmax + σmin)/2; σa = (σmax − σmin)/2; R = σmin / σmax
Mean stress, stress amplitude (Pa) and stress ratio of a fatigue cycle.
σa / Se + σm / Su = 1
Goodman line: Se = endurance limit, Su = ultimate tensile strength (Pa). Combinations on or below the line are safe for infinite life (divide by a factor of safety for design).
σa = σf′·(2Nf)^b
Basquin's law for high-cycle fatigue: σf′ = fatigue strength coefficient (Pa), b = fatigue strength exponent (about −0.05 to −0.12), Nf = cycles to failure; both constants come from test data.
ε̇s = A·σⁿ·exp(−Qc / (R·T))
Steady-state creep rate (s⁻¹); A, n (stress exponent) from data; Qc = creep activation energy (J/mol); R = 8.314 J/(mol·K); T in K.
LMP = T·(C + log10 tr)
Larson–Miller parameter; T in K, tr = rupture time in hours, C ≈ 20 for steels.
Worked examples
Example 1 (standard): Brinell and Vickers. (a) 10 mm ball, 3000 kgf load, indentation 4.0 mm.
- √(D² − d²) = √(100 − 16) = 9.165 mm; D − 9.165 = 0.835 mm.
- HB = 2 × 3000 / (π × 10 × 0.835) = 6000 / 26.23 = 229 HB.
- Estimated UTS ≈ 3.45 × 229 ≈ 790 MPa. (b) Vickers, 30 kgf, mean diagonal 0.45 mm: HV = 1.8544 × 30 / 0.45² = 275 HV.
Example 2 (standard): Charpy energy. Hammer mass 20 kg falls from h1 = 1.5 m and rises to h2 = 0.9 m after breaking the specimen. E_abs = 20 × 9.81 × (1.5 − 0.9) = 117.7 J.
Example 3 (GATE level): fatigue with mean stress, and creep extrapolation. (a) A steel has Su = 600 MPa and Se = 300 MPa. A part carries σmax = 250 MPa, σmin = −50 MPa. Is it safe for infinite life?
- σm = (250 − 50)/2 = 100 MPa; σa = (250 + 50)/2 = 150 MPa; R = −0.2.
- Goodman: σa/Se + σm/Su = 150/300 + 100/600 = 0.5 + 0.167 = 0.667 < 1, so safe (factor of safety 1/0.667 = 1.5). (b) For σf′ = 900 MPa and b = −0.1, the life at σa = 300 MPa (zero mean): 2Nf = (300/900)^(1/−0.1) = 3¹⁰ = 59 049, so Nf ≈ 2.95 × 10⁴ cycles. (c) A steel ruptures in 1000 h at 800 K under a given stress. With C = 20, LMP = 800 × (20 + 3) = 18 400. At 900 K and the same stress: log tr = 18 400/900 − 20 = 0.444, so tr ≈ 2.8 h.
Common mistakes
- Putting F in newtons into the Brinell formula without the 0.102 factor (answers 9.81 times too large).
- Taking Charpy energy as m·g·h1; the absorbed energy is the difference between the initial and final heights.
- Calling hardness tests fully non-destructive; they leave an indentation.
- Confusing stress range (σmax − σmin) with amplitude (half the range).
- Assuming aluminium alloys have an endurance limit.
- Using °C in the Larson–Miller parameter or the Arrhenius creep law.
- Designing on primary creep; the steady-state rate and rupture life are the design inputs.
For GATE PI
Expect one-mark questions on which indenter each hardness test uses, Charpy versus Izod, the ductile-to-brittle transition and which structures show it, the three stages of creep, and factors that improve fatigue life. Numericals cover Brinell/Vickers numbers, pendulum energy, mean and alternating stress with Goodman or Soderberg lines, S–N (Basquin) life, and creep strain from a steady-state rate. Practise unit handling (kgf vs N) and log-scale calculations.
Quick check
- Which hardness test reads depth of penetration rather than indent size?
- σmax = 200 MPa and σmin = −200 MPa. What are σm, σa and R?
- Why is austenitic stainless steel chosen for liquid-nitrogen tanks?
- A material creeps at a steady 10⁻⁴ per hour. What creep strain accumulates in 1000 h of steady-state creep?
- Name two treatments that raise the fatigue life of a shaft by putting its surface in compression.
Answers: 1. Rockwell; 2. 0 MPa, 200 MPa, −1; 3. FCC structure, no ductile-to-brittle transition; 4. 0.1 (10 %); 5. Shot peening and carburising (or nitriding, surface rolling).
Interview questions
All Engineering Materials interview questionsTry answering each one aloud before you open it.
1.What is hardness in the context of engineering materials?Concept
Hardness is a measure of a material's resistance to deformation, particularly permanent deformation, scratching, cutting, or abrasion. It is an important property for materials that are used in applications where wear resistance is critical.
2.Explain the impact test and its significance in material testing.Concept
An impact test (Charpy or Izod) breaks a standard notched specimen with a swinging pendulum and records the energy absorbed, m·g·(h1 − h2), as a measure of notch toughness at a high strain rate. Charpy supports the specimen as a simple beam struck behind the notch; Izod clamps it as a cantilever. Running the test over a range of temperatures reveals the ductile-to-brittle transition of ferritic steels, which is used to qualify steels for ships, pipelines and pressure vessels in cold service.
3.What is fatigue in materials, and why is it important to test for it?Concept
Fatigue refers to the weakening of a material caused by repeatedly applied loads, typically below the material's ultimate tensile strength. Testing for fatigue is important because it helps predict the lifespan of a material under cyclic loading conditions, which is critical for components like bridges, aircraft, and machinery that experience repeated stress.
4.Define creep in materials and describe a situation where it might be a concern.Concept
Creep is the slow, permanent deformation of a material under constant stress over a long period, especially at high temperatures. It is a concern in applications like turbine blades in jet engines, where materials are exposed to high temperatures and stresses for extended periods.
5.Why is the Rockwell hardness test commonly used in industry?Application
Rockwell measures the depth of penetration under a major load after a minor preload, and the hardness number is read directly from a dial or display, so a test takes seconds and needs no microscope measurement of the indent. The preload removes the effect of surface roughness and backlash. Different scales (HRC with a diamond cone for hardened steel, HRB with a steel ball for softer metals) cover a wide range. It leaves only a small dent, so finished parts can usually be checked, which makes it ideal for production heat-treatment checks.
6.What happens to a material's impact resistance at low temperatures?Application
At low temperatures, many materials become more brittle, which reduces their impact resistance. This means they are more likely to fracture or fail when subjected to sudden forces or impacts. This behavior is particularly important to consider in applications like pipelines or structural components in cold environments.
7.How does surface finish affect the fatigue life of a material?Application
A rough surface finish can act as a stress concentrator, which can initiate cracks and reduce the fatigue life of a material. Conversely, a smooth surface finish can help distribute stress more evenly and improve fatigue resistance. Therefore, surface finish is an important factor in designing components that will experience cyclic loading.
8.A material has a creep rate of 0.0001 per hour at a constant stress. How much strain will it experience after 1000 hours?Numerical
The total strain experienced by the material can be calculated by multiplying the creep rate by the time. Here, the creep rate is 0.0001 per hour, and the time is 1000 hours. Therefore, the total strain = 0.0001/hour × 1000 hours = 0.1.
9.Why is it important to consider both hardness and toughness when selecting materials for engineering applications?Application
Hardness and toughness are both critical properties that affect a material's performance. Hardness is important for wear resistance, while toughness is crucial for absorbing energy and resisting fracture. A balance between these properties is often necessary to ensure that a material can withstand both surface wear and impact or shock loading in its intended application.
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