Frequency and phase modulation
FM and PM vary the carrier angle: deviation, modulation index, Bessel spectrum, Carson's rule, generation and detection.
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Why it matters
Frequency modulation (FM) and phase modulation (PM) carry information in the angle of a constant-amplitude carrier. Because the envelope is constant, amplitude noise and non-linear power amplifiers do little harm, which is why FM is used in broadcast radio, two-way radio, telemetry links and many sensor transmitters. In instrumentation, frequency-output sensors and FM telemetry rely on exactly the same ideas.
Key ideas
Angle modulation. A carrier is written as s(t) = A_c·cos θ_i(t). The instantaneous frequency is the rate of change of the angle: f_i(t) = (1/2π)·dθ_i/dt. The amplitude A_c never changes, so the transmitted power is A_c²/2 (into 1 Ω) whatever the message.
Phase modulation. The phase deviates in direct proportion to the message: θ_i(t) = 2πf_c·t + k_p·m(t), where k_p is the phase sensitivity (rad/V). The peak phase deviation is Δφ = k_p·|m|max, and for a single tone this is the modulation index of PM.
Frequency modulation. The instantaneous frequency deviates in proportion to the message: f_i(t) = f_c + k_f·m(t), where k_f is the frequency sensitivity (Hz/V). The phase is then the integral of the message: θ_i(t) = 2πf_c·t + 2πk_f·∫m(τ)dτ. The peak frequency deviation is Δf = k_f·|m|max.
FM and PM are relatives. FM of m(t) equals PM of the integral of m(t); PM of m(t) equals FM of dm/dt. So an FM signal can be generated by integrating the message and feeding a phase modulator (the indirect, Armstrong method), and the two are indistinguishable for a single tone unless you vary the tone frequency.
Single-tone FM. For m(t) = A_m·cos(2πf_m·t), the FM signal is s(t) = A_c·cos(2πf_c·t + β·sin 2πf_m·t) with modulation index β = Δf/f_m (dimensionless, in radians of peak phase deviation). Note that for FM, Δf depends only on the message amplitude, so β falls as f_m rises. For PM, β = Δφ = k_p·A_m is independent of f_m, so the equivalent frequency deviation Δf = β·f_m rises with f_m.
Spectrum. The single-tone FM signal expands into a carrier and an infinite set of sidebands at f_c ± n·f_m with amplitudes A_c·J_n(β) (Bessel functions of the first kind). The carrier amplitude J_0(β) vanishes at β ≈ 2.405, which is used to calibrate deviation meters. Total power stays A_c²/2 because the Bessel terms satisfy ΣJ_n²(β) = 1.
Narrowband vs wideband. If β is small (below about 0.3), only the first pair of sidebands matters: narrowband FM (NBFM) occupies about 2f_m, like AM, but its sidebands are in phase quadrature with the carrier. When β is large (wideband FM, WBFM), the bandwidth is roughly 2Δf.
Carson's rule. About 98% of the power lies within B ≈ 2(Δf + f_m) = 2(β + 1)·f_m. For a general message use the peak deviation and the highest message frequency W: B ≈ 2(Δf + W); the ratio D = Δf/W is the deviation ratio.
Noise and trade-off. Above threshold, FM trades bandwidth for SNR: the figure of merit (output SNR relative to baseband) is 3β²/2 for a tone. Below the threshold carrier-to-noise ratio (about 10 dB at the discriminator input) the output breaks down sharply. FM output noise spectral density grows as f², which is why broadcast FM uses pre-emphasis at the transmitter and de-emphasis at the receiver; PM output noise is flat.
Generation and detection. Direct FM: a VCO or varactor-tuned oscillator. Indirect FM: NBFM via a phase modulator, then frequency multipliers to raise Δf (multiplying the carrier by n multiplies Δf and β by n). Detection: a slope or balanced discriminator, a Foster–Seeley or ratio detector, a zero-crossing counter, or a phase-locked loop (PLL). A limiter before the discriminator removes amplitude variations.
Formulas
f_i(t) = f_c + k_f·m(t)
f_i instantaneous frequency (Hz), f_c carrier frequency (Hz), k_f frequency sensitivity (Hz/V), m(t) message (V).
Δf = k_f·|m(t)|max
Δf peak frequency deviation (Hz).
θ_i(t) = 2πf_c·t + k_p·m(t) (PM), Δφ = k_p·|m(t)|max
k_p phase sensitivity (rad/V), Δφ peak phase deviation (rad).
β = Δf/f_m (single-tone FM; for PM β = Δφ)
β modulation index (rad, dimensionless), f_m tone frequency (Hz).
s(t) = A_c·Σ J_n(β)·cos[2π(f_c + n·f_m)t], n from −∞ to +∞
A_c carrier amplitude (V), J_n Bessel function of order n.
B ≈ 2(Δf + W) = 2(D + 1)·W (Carson's rule)
B transmission bandwidth (Hz), W highest message frequency (Hz), D = Δf/W deviation ratio.
P = A_c²/2 (average power into 1 Ω, independent of modulation)
Worked examples
Example 1 (standard). An FM broadcast station has peak deviation Δf = 75 kHz and the highest audio frequency is W = 15 kHz. Find the deviation ratio and the Carson bandwidth.
D = Δf/W = 75/15 = 5.B = 2(Δf + W) = 2(75 + 15) kHz.B = 2 × 90 kHz = 180 kHz. Answer: D = 5, B ≈ 180 kHz. (Channels are spaced 200 kHz apart, leaving a guard band.)
Example 2 (GATE level). The message m(t) = 2·cos(2π·2000·t) V is applied (a) to an FM modulator with k_f = 5 kHz/V and (b) to a PM modulator with k_p = 2 rad/V. Find the Carson bandwidth in each case, and then repeat with the tone frequency doubled to 4 kHz (same amplitude).
- FM:
Δf = k_f·A_m = 5 kHz/V × 2 V = 10 kHz;β = Δf/f_m = 10/2 = 5;B = 2(10 + 2) kHz = 24 kHz. - PM:
β = Δφ = k_p·A_m = 2 × 2 = 4 rad; equivalentΔf = β·f_m = 4 × 2 kHz = 8 kHz;B = 2(8 + 2) kHz = 20 kHz. - FM at f_m = 4 kHz: Δf stays 10 kHz,
β = 10/4 = 2.5;B = 2(10 + 4) = 28 kHz. - PM at f_m = 4 kHz: β stays 4 rad,
Δf = 4 × 4 = 16 kHz;B = 2(16 + 4) = 40 kHz. Answer: FM 24 kHz → 28 kHz; PM 20 kHz → 40 kHz. Doubling f_m barely changes FM bandwidth but doubles PM bandwidth — the cleanest way to tell the two apart.
Example 3 (indirect FM). An NBFM stage produces Δf = 25 Hz at a carrier of 200 kHz. How much frequency multiplication gives Δf = 75 kHz?
- Multiplication factor
n = 75 000/25 = 3000. - The carrier would become 3000 × 200 kHz = 600 MHz, so a mixer is used part-way to bring the carrier back down; mixing shifts the carrier but does not change Δf. Answer: n = 3000.
Common mistakes
- Using
β = Δf/f_mfor PM. For PM the index is the peak phase deviation itself, k_p·A_m, in radians. - Thinking a mixer changes the deviation. Only frequency multiplication scales Δf and β; mixing only translates the carrier.
- Writing
cos(2π·f_i(t)·t)for the FM signal. The phase is the integral of 2πf_i(t), not f_i(t) multiplied by t. - Forgetting the factor 2 in Carson's rule, or using f_c in it. The carrier frequency never enters the bandwidth.
- Assuming FM power rises with modulation. The total power is fixed at A_c²/2; modulation only redistributes it among carrier and sidebands.
- Treating NBFM as identical to AM. The bandwidth is the same (2f_m), but the NBFM sideband phases differ, so an envelope detector cannot recover it.
For GATE IN
- Numericals on Δf, β and Carson bandwidth, often with a given s(t) expression from which you read β and f_m.
- Distinguishing FM from PM when the tone frequency or amplitude changes.
- Frequency multiplier and mixer chains in Armstrong transmitters: track f_c and Δf separately.
- Instantaneous frequency of a given angle expression by differentiation.
- Bessel-function sideband questions: carrier null at β ≈ 2.405, power in a given set of sidebands.
Quick check
- s(t) = 10·cos(2π·10⁸·t + 4·sin 2π·10³·t). What are β and Δf?
- What is the average power of the signal in Q1 into 1 Ω?
- In PM, what happens to bandwidth when the tone frequency doubles?
- Which circuit block raises the frequency deviation in an Armstrong transmitter? Answers: 1. β = 4, Δf = 4 kHz. 2. 50 W. 3. It roughly doubles (β constant, Δf = β·f_m doubles). 4. The frequency multiplier.
Interview questions
All Communication and Optical Instrumentation interview questionsTry answering each one aloud before you open it.
1.What is frequency modulation (FM) and how does it differ from amplitude modulation (AM)?Concept
Frequency modulation (FM) is a technique where the frequency of the carrier wave is varied in accordance with the amplitude of the input signal. In contrast, amplitude modulation (AM) involves varying the amplitude of the carrier wave while keeping its frequency constant. FM is less susceptible to noise and interference compared to AM, which makes it preferable for high-fidelity broadcasts.
2.Explain the concept of phase modulation (PM) and its relationship with frequency modulation.Concept
In PM the carrier phase deviates in direct proportion to the message, θ_i(t) = 2πf_c·t + k_p·m(t). Since instantaneous frequency is the derivative of phase, PM of m(t) is the same as FM of dm/dt, and FM of m(t) is the same as PM of the integral of m(t). This is why an Armstrong transmitter makes FM by integrating the message and driving a phase modulator. For a single tone the two look identical; they differ in how bandwidth responds to changes in the tone frequency.
3.Why is frequency modulation preferred over amplitude modulation for FM radio broadcasting?Application
The information is in the zero crossings, not the envelope, so a limiter strips amplitude noise and interference before detection. Above threshold, wideband FM trades bandwidth for SNR: the output SNR improvement grows roughly as β², and pre-emphasis/de-emphasis add further gain against the f²-shaped FM noise. FM also shows the capture effect, suppressing a weaker co-channel station, and its constant envelope allows efficient non-linear class-C transmitter amplifiers. The cost is bandwidth: about 180–200 kHz per channel versus 10 kHz for AM broadcast.
4.What happens to the bandwidth of a signal when frequency modulation is applied?Application
When frequency modulation is applied, the bandwidth of the signal increases. The bandwidth of an FM signal is determined by the frequency deviation and the modulating signal frequency. According to Carson's Rule, the bandwidth is approximately twice the sum of the maximum frequency deviation and the highest frequency in the modulating signal.
5.How does phase modulation affect the bandwidth of a signal compared to frequency modulation?Application
Both are wideband for large index and both can be estimated with Carson's rule, B ≈ 2(Δf + f_m). The difference is in what is fixed: in FM the frequency deviation Δf = k_f·A_m is fixed by the message amplitude, so β = Δf/f_m falls as f_m rises and bandwidth changes little. In PM the index β = Δφ = k_p·A_m is fixed in radians, so the equivalent deviation β·f_m grows with f_m and the bandwidth grows almost proportionally with the message frequency.
6.Explain the role of the modulation index in frequency modulation.Concept
The modulation index in frequency modulation is a measure of the extent of frequency variation in the carrier wave. It is defined as the ratio of the frequency deviation to the modulating frequency. A higher modulation index indicates a greater frequency deviation, which results in a wider bandwidth and potentially better signal quality. However, it also requires more spectrum space.
7.Calculate the bandwidth of an FM signal with a maximum frequency deviation of 75 kHz and a maximum modulating frequency of 15 kHz.Numerical
Using Carson's Rule, the bandwidth (BW) of an FM signal can be calculated as: BW = 2 × (Δf + fm), where Δf is the maximum frequency deviation and fm is the maximum modulating frequency. Substituting the given values: BW = 2 × (75 kHz + 15 kHz) = 2 × 90 kHz = 180 kHz.
8.If the modulation index of an FM signal is 5 and the modulating frequency is 10 kHz, what is the frequency deviation?Numerical
The modulation index (β) in FM is given by the formula β = Δf / fm, where Δf is the frequency deviation and fm is the modulating frequency. Rearranging the formula to find Δf gives Δf = β × fm. Substituting the given values: Δf = 5 × 10 kHz = 50 kHz.
9.Discuss the impact of noise on phase modulation compared to frequency modulation.Application
Both are constant-envelope, so a limiter removes amplitude noise in either case; what matters is the noise that perturbs the phase. After a phase detector the output noise spectral density is flat across the message band, while after a frequency discriminator (a differentiator of phase) it rises as f², so FM high-frequency message components see more noise. FM therefore uses pre-emphasis and de-emphasis, and a pre-emphasised FM system behaves partly like PM at high audio frequencies. For a tone, FM's figure of merit is 3β²/2 versus β²/2 for PM at equal index, so FM is better for wideband analog use.
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