Flow measurement: orifice, venturi, pitot tube, rotameter

Venturi and orifice meters with the velocity-of-approach factor and permanent losses, pitot-static tubes for local velocity, and the rotameter force balance and recalibration.

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Why it matters

Every material balance in a plant depends on measured flows. Orifice plates are the most common industrial flow element, venturis are used where pressure loss is costly, pitot tubes survey velocity profiles in ducts and stacks, and rotameters are the everyday meter on lab and utility lines. Each works by converting a flow into a pressure difference or a force, so each is a direct application of Bernoulli, continuity and the momentum balance.

Key ideas

Obstruction (variable-head) meters. A constriction accelerates the fluid; continuity and Bernoulli between the upstream section (1) and the constriction (2) give the ideal flow, and an empirical coefficient corrects for friction and contraction: Q = C·A₂·√[2Δp/(ρ(1 − β⁴))], with β = d₂/d₁ the diameter ratio. The factor 1/√(1 − β⁴) is the velocity-of-approach factor. Because Q ∝ √Δp, these meters have a limited turndown (about 3:1 to 4:1 for good accuracy) — a 10:1 flow range needs a 100:1 Δp range.

Venturi meter.

  • Converging cone (about 21°), throat, then a long diverging cone (about 5–15°) that recovers most of the pressure.
  • Coefficient of discharge C_v ≈ 0.95–0.99.
  • Permanent pressure loss only about 10–15 % of the measured Δp; low wear, handles slurries; but long and expensive.

Orifice meter.

  • A thin plate with a sharp-edged concentric hole (bevelled edge faces downstream) clamped between flanges; taps at flange, corner or vena-contracta positions.
  • The jet contracts to a vena contracta downstream of the plate, so C_o is low, about 0.61–0.62 for sharp-edged plates (it depends on β, Re and tap location; take it from the standard or data book).
  • Permanent loss is large: roughly (1 − β²)Δp, i.e. 60–75 % of the measured Δp for usual β.
  • Cheap, compact, easy to change; needs straight upstream pipe runs (often 10–40 D depending on fittings) for a developed profile.

Pitot and pitot-static tubes.

  • A tube facing the flow brings fluid to rest and reads the stagnation pressure p₀ = p + ρV²/2; a static tap reads p. Their difference gives the local velocity V = C·√(2(p₀ − p)/ρ), C ≈ 0.98–1.0.
  • Measures point velocity; to get flow rate, traverse the duct and integrate (or use the centreline velocity with V_avg/V_max ≈ 0.5 laminar, ≈ 0.8–0.85 turbulent).
  • Negligible pressure loss; unsuitable for dirty fluids (plugging) or very low velocities (tiny Δp). Must be aligned with the flow.

Rotameter (variable-area meter).

  • A float in a vertical tapered tube rises until the annular area between float and tube is large enough that the pressure difference across the float balances its buoyancy-corrected weight.
  • The pressure drop across the float is constant: Δp = V_f(ρ_f − ρ)g/A_f. Flow varies with annular area, so the float height is nearly linear in flow; turndown about 10:1.
  • Calibrated for a particular fluid; a correction for a different density is Q₂/Q₁ = √[(ρ_f − ρ₂)ρ₁/((ρ_f − ρ₁)ρ₂)].
  • Must be vertical; usually glass or with magnetic coupling for opaque tubes; not for high pressure or dirty fluids.

Other meters (brief). Magnetic (conductive liquids, no obstruction), turbine, vortex-shedding, ultrasonic, Coriolis (direct mass flow), positive-displacement and notches/weirs for open channels.

Formulas

  • Q = C·A₂·√[2·Δp/(ρ·(1 − β⁴))] — venturi or orifice; Q (m³/s), A₂ throat or orifice area (m²), Δp (Pa), ρ (kg/m³), β = d₂/d₁.
  • Δp = (ρ_m − ρ)·g·R — Δp from a differential manometer reading R (m), tappings at equal level.
  • V = C·√[2·(p₀ − p)/ρ] — pitot-static tube, local velocity (m/s).
  • Δp_loss ≈ (1 − β²)·Δp — approximate permanent loss of an orifice.
  • Δp = V_f·(ρ_f − ρ)·g/A_f — rotameter pressure drop; V_f float volume (m³), A_f float cross-section (m²), ρ_f float density.
  • Q = C_R·A_a·√[2·g·V_f·(ρ_f − ρ)/(A_f·ρ)] — rotameter flow; A_a annular area (m²), C_R discharge coefficient.

Worked examples

Example 1 (standard). A venturi meter with 150 mm inlet and 75 mm throat carries water (ρ = 1000 kg/m³). A mercury–water differential manometer (ρ_m = 13 600 kg/m³) reads 0.2 m. C_v = 0.98. Find Q.

  1. Δp = (ρ_m − ρ)gR = 12 600 × 9.81 × 0.2 = 24 721 Pa.
  2. β = 75/150 = 0.5; 1 − β⁴ = 0.9375. A₂ = (π/4)(0.075)² = 4.418 × 10⁻³ m².
  3. Q = C·A₂·√[2Δp/(ρ(1 − β⁴))] = 0.98 × 4.418 × 10⁻³ × √(2 × 24 721 / 937.5) = 0.98 × 4.418 × 10⁻³ × 7.262 = 0.0314 m³/s. Q ≈ 0.0314 m³/s (31.4 L/s).

Example 2 (GATE level). A sharp-edged orifice of 50 mm diameter is installed in a 100 mm water line (ρ = 1000 kg/m³). The measured pressure difference is 20 kPa and C_o = 0.62. Find (a) the flow rate, (b) the approximate permanent pressure loss, and (c) the pressure difference if the flow doubles.

  1. β = 0.5; A₀ = (π/4)(0.05)² = 1.963 × 10⁻³ m².
  2. Q = 0.62 × 1.963 × 10⁻³ × √(2 × 20 000 / (1000 × 0.9375)) = 0.62 × 1.963 × 10⁻³ × 6.532 = 7.95 × 10⁻³ m³/s.
  3. Permanent loss ≈ (1 − β²)Δp = 0.75 × 20 = 15 kPa.
  4. Δp ∝ Q², so doubling Q gives 4 × 20 = 80 kPa. (a) Q ≈ 7.95 L/s; (b) ≈ 15 kPa lost permanently; (c) 80 kPa. A venturi of the same β would read only about 8 kPa at this flow (since C_v ≈ 0.98) and lose permanently only about 1 kPa.

Example 3 (pitot tube). A pitot-static tube in an air duct (ρ = 1.2 kg/m³) is connected to a water manometer reading 50 mm. Δp = 1000 × 9.81 × 0.05 = 490.5 Pa (air column negligible); V = √(2 × 490.5/1.2) = 28.6 m/s at that point.

Common mistakes

  • Using the pipe area instead of the throat/orifice area in the meter equation, or omitting the velocity-of-approach factor.
  • Using ρ_m·g·R instead of (ρ_m − ρ)·g·R when the manometer limbs contain the flowing liquid.
  • Confusing the measured Δp with the permanent pressure loss.
  • Treating a pitot reading as the average velocity.
  • Using a rotameter calibrated for water on another liquid without a density correction.
  • Assuming Q ∝ Δp; it is Q ∝ √Δp for obstruction meters.

For GATE CH

Expect venturi and orifice numericals with manometer readings, comparison of permanent losses, pitot-tube velocity calculations, rotameter force-balance and recalibration problems, and conceptual questions on which meter suits a given duty. Practise combining the manometer equation with the meter equation in one clean chain.

Quick check

  1. If the flow through an orifice meter triples, by what factor does Δp change?
  2. Which meter has a nearly constant pressure drop across its range?
  3. Why does a venturi have a higher discharge coefficient than an orifice?
  4. Does a pitot tube measure average velocity?

Answers: 1. 9 times. 2. The rotameter. 3. Its smooth convergence avoids a vena contracta and separation, so the flow fills the throat. 4. No, only the local velocity at its tip.

Flow Measurement with Orifice Meter

Adjust the pressure drop and fluid density to see how the flow rate changes through an orifice meter. Observe the relationship between these variables and the flow rate.

Equations used
  • Q = C_d * A * sqrt(2 * ΔP / ρ) — Q flow rate, C_d discharge coefficient, A area of the orifice, ΔP pressure drop, ρ fluid density

Try answering each one aloud before you open it.

  1. 1.What is an orifice meter and how does it work?Concept

    An orifice meter is a device used to measure the flow rate of a fluid by introducing a restriction in the flow path. It consists of a flat plate with a hole (orifice) in the middle. As fluid flows through the orifice, the velocity increases and the pressure decreases. The flow rate can be determined by measuring the pressure difference between the upstream and downstream sides of the orifice.

  2. 2.Explain the working principle of a Venturi meter.Concept

    A Venturi meter measures fluid flow by narrowing the flow path, which increases the fluid velocity and decreases its pressure. It consists of a converging section, a throat, and a diverging section. The pressure difference between the inlet and the throat is used to calculate the flow rate using Bernoulli's equation.

  3. 3.What is a Pitot tube and how is it used to measure fluid flow?Concept

    A Pitot tube is a device used to measure fluid flow velocity. It consists of a tube pointing directly into the fluid flow. The tube measures the stagnation pressure, which is the sum of the static and dynamic pressure. By comparing this with the static pressure, the fluid velocity can be calculated using Bernoulli's equation.

  4. 4.Describe the working principle of a rotameter.Concept

    A rotameter is a type of variable area flow meter that measures the flow rate of a fluid in a closed tube. It consists of a tapered tube and a float inside it. As fluid flows through the tube, it causes the float to rise. The height of the float is proportional to the flow rate, and it can be read on a scale marked on the tube.

  5. 5.Why is a Venturi meter preferred over an orifice meter in some applications?Application

    A Venturi meter is preferred over an orifice meter in applications where a lower pressure drop is desired. The Venturi meter has a more gradual change in cross-sectional area, which results in less energy loss compared to the abrupt change in an orifice meter. This makes the Venturi meter more efficient for measuring flow in systems where maintaining pressure is important.

  6. 6.What happens if the orifice plate in an orifice meter is installed backwards?Application

    A standard plate has a sharp square edge facing upstream and a bevel on the downstream side. Installed backwards, the fluid meets the bevelled edge, which acts like a short rounded or conical entrance: the jet contracts less, the discharge coefficient rises, and the measured Δp for a given flow falls. The meter therefore under-reads flow, often by several per cent or more. The plate's tab is stamped with the inlet side precisely to avoid this, and it is a common commissioning check.

  7. 7.How does the presence of air bubbles affect the accuracy of a rotameter?Application

    A rotameter is calibrated for a single-phase fluid of known density, because the float settles where drag and pressure difference balance its buoyancy-corrected weight. Gas bubbles make the effective density of the stream uncertain, so the volumetric reading no longer matches the liquid flow. Bubbles also collect under the float or strike it, making it bounce and giving an unsteady, unreliable reading. The remedy is to vent or remove entrained gas upstream, or use a meter suited to two-phase flow.

  8. 8.Calculate the ideal flow rate of water (ρ = 1000 kg/m³) through a venturi meter with an inlet diameter of 0.1 m and a throat diameter of 0.05 m, for a pressure difference of 5000 Pa.Numerical

    From continuity and Bernoulli, Q = A₂√[2Δp/(ρ(1 − β⁴))]. Here A₂ = (π/4)(0.05)² = 1.963 × 10⁻³ m² and β = 0.5, so 1 − β⁴ = 0.9375. Then Q = 1.963 × 10⁻³ × √(2 × 5000 / 937.5) = 1.963 × 10⁻³ × 3.266 = 6.41 × 10⁻³ m³/s, about 6.4 L/s. A real venturi would deliver about 98 % of this (C_v ≈ 0.98).

  9. 9.A Pitot tube measures a stagnation pressure of 1200 Pa and a static pressure of 1000 Pa in a fluid with a density of 1.2 kg/m³. Calculate the fluid velocity.Numerical

    The fluid velocity can be calculated using the equation: v = √(2(ΔP)/ρ), where ΔP is the difference between stagnation and static pressure, and ρ is the fluid density. ΔP = 1200 - 1000 = 200 Pa. v = √(2 * 200 / 1.2) = √(333.33) = 18.26 m/s.

  10. 10.What limits the use of a Pitot tube for flow measurement?Application

    A pitot tube gives only the local time-averaged velocity at its tip, so flow rate needs a traverse or an assumed profile. In turbulent flow the reading fluctuates, but a damped manometer or transmitter averages it acceptably, so turbulence itself is not the main problem. The real limits are low velocities, where the dynamic pressure ρV²/2 is too small to read accurately; misalignment with the flow; plugging of the small holes by dirty or fibrous fluids; and gases at high Mach number, which need compressibility corrections.

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