Belt, rope and chain drives
Flat, V-belt, rope and chain drives: velocity ratio, slip and creep, belt length and angle of contact, tension ratio, centrifugal tension and maximum power, initial tension, and sprocket geometry with chordal action.
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Why it matters
Belts, ropes and chains transmit power between shafts that are too far apart for gears: from motors to compressors, fans, conveyors, machine tools and two-wheelers. They are cheap, tolerate misalignment and (belts) absorb shock, but their capacity is limited by friction and by the tension the belt or chain can carry. Designing one means finding the tensions, the power and the speed at which the drive works best.
Key ideas
Types.
- Flat belts: rectangular section, run on crowned pulleys; suit long centre distances and high speeds; efficiency about 95–98 %.
- V-belts: trapezoidal section wedging into a grooved pulley. The wedge action multiplies the normal force, so a V-belt transmits more power for the same tension and suits short centre distances and multiple-belt drives. Wedge friction and flexing make them slightly less efficient than flat belts.
- Rope drives: fibre or wire ropes in grooved sheaves, used to carry large power over long distances (mill drives, hoists, cranes); the analysis is the same as for a V-belt.
- Timing (toothed) belts: teeth engage the pulley, giving a positive drive with no slip.
- Chain drives: roller chains on sprockets give a positive, no-slip drive with a fixed average speed ratio, carry high loads at moderate speeds and do not need initial tension, but need lubrication and are noisier.
Velocity ratio, slip and creep. Without slip the belt speed is the same on both pulleys, so N₂/N₁ = d₁/d₂. Including belt thickness t, the effective diameters are d + t. Slip is the bulk sliding of the belt on the pulley when friction is insufficient; it is expressed as a percentage s and reduces the driven speed. Creep is the small relative motion caused by the belt stretching more on the tight side than the slack side; it is always present in a friction belt and also lowers the speed slightly.
Open and crossed belts. In an open drive both pulleys turn the same way and the smaller pulley has the smaller angle of contact, so it governs slipping. In a crossed drive the pulleys turn in opposite directions and both have the same, larger angle of contact.
Tension ratio. As the belt wraps the pulley, friction lets the tension rise from T₂ (slack side) to T₁ (tight side). Integrating over the arc gives the capstan equation T₁/T₂ = e^(μθ), with θ in radians on the pulley where slipping would start. For a V-belt or rope, the wedge raises the normal reaction by 1/sin α (α = half the groove angle), so μ is replaced by μ/sin α.
Centrifugal tension. At speed, each element of belt needs a centripetal force; this appears as an extra tension Tc = m·v² in both sides. It does not change the power (it cancels in T₁ − T₂) but uses up part of the allowable tension. With T_max fixed, T₁ = T_max − Tc, and the power is maximum when Tc = T_max/3, at v = √(T_max/(3m)).
Initial tension. A belt is fitted with an initial tension T₀; in use the tight side gains and the slack side loses roughly equally, so T₀ = (T₁ + T₂)/2, or (T₁ + T₂ + 2Tc)/2 when centrifugal tension is counted in T₁ and T₂.
Chains. A sprocket of z teeth and chain pitch p has pitch diameter d = p/sin(180°/z). The chain wraps as a polygon, so the chain speed fluctuates between v_max and v_max·cos(180°/z) every tooth (chordal or polygon action). More teeth on the small sprocket (17 or more is common) reduce this fluctuation, noise and wear.
Formulas
Velocity ratio: N₂/N₁ = (d₁ + t)/(d₂ + t) × (1 − s/100) — N in rev/min, d and t in m, s total slip in %.
Belt speed: v = π·d·N/60 (m/s, d in m, N in rev/min).
Open belt: sin α = (r₂ − r₁)/C; angle of contact on the small pulley θ = π − 2α; length L = π(r₁ + r₂) + 2C + (r₂ − r₁)²/C.
Crossed belt: sin α = (r₁ + r₂)/C; θ = π + 2α; length L = π(r₁ + r₂) + 2C + (r₁ + r₂)²/C.
Flat belt tension ratio: T₁/T₂ = e^(μ·θ) (θ in rad). V-belt or rope: T₁/T₂ = e^(μ·θ/sin α), α half groove angle.
Power: P = (T₁ − T₂)·v (W, T in N, v in m/s).
Centrifugal tension: Tc = m·v² (N, m mass per metre of belt in kg/m). T₁ = T_max − Tc; T_max = σ_allow·b·t for a flat belt.
Maximum power: Tc = T_max/3, v_opt = √(T_max/(3m)).
Initial tension: T₀ = (T₁ + T₂ + 2Tc)/2 (with Tc excluded from T₁ and T₂).
Chain: d = p/sin(180°/z); average speed v = z·p·N/60 (m/s, p in m); speed variation v_min/v_max = cos(180°/z).
Worked examples
Example 1 (standard). An open flat belt connects a 400 mm driving pulley at 720 rev/min to a 1000 mm driven pulley; centre distance 2 m. μ = 0.3, belt mass 0.8 kg/m, maximum permissible tension 2000 N. Neglecting slip and thickness, find the power transmitted.
v = π × 0.4 × 720/60 = 15.08 m/s; driven speedN₂ = 720 × 0.4/1.0 = 288 rev/min.Tc = m·v² = 0.8 × 15.08² = 181.9 N;T₁ = 2000 − 181.9 = 1818.1 N.sin α = (0.5 − 0.2)/2 = 0.15,α = 8.63°;θ = 180 − 2 × 8.63 = 162.75° = 2.840 rad(small pulley).T₁/T₂ = e^(0.3 × 2.840) = 2.345;T₂ = 1818.1/2.345 = 775.4 N.P = (T₁ − T₂)·v = (1818.1 − 775.4) × 15.08 = 15 720 W.- P ≈ 15.7 kW. (Belt length
L = π × 0.7 + 4 + 0.3²/2 = 6.244 m.)
Example 2 (GATE level). A V-belt has a groove angle of 40°, μ = 0.25, angle of contact 165° on the smaller pulley, mass 0.35 kg/m and maximum allowable tension 900 N. Find the belt speed for maximum power and that power.
v_opt = √(T_max/(3m)) = √(900/(3 × 0.35)) = 29.28 m/s.Tc = T_max/3 = 300 N;T₁ = 900 − 300 = 600 N.θ = 165° = 2.880 rad;μθ/sin α = 0.25 × 2.880/sin 20° = 2.105;T₁/T₂ = e^2.105 = 8.207.T₂ = 600/8.207 = 73.1 N.P = (600 − 73.1) × 29.28 = 15 430 W.- v ≈ 29.3 m/s, P_max ≈ 15.4 kW. A flat belt with the same μ and θ would have T₁/T₂ = e^(0.72) = 2.05 only, which shows the wedge advantage.
Common mistakes
- Using θ in degrees in e^(μθ).
- Taking the angle of contact of the larger pulley in an open drive; slipping starts on the smaller pulley.
- Using the full groove angle instead of half of it in the V-belt formula.
- Forgetting that T_max includes centrifugal tension, so T₁ = T_max − Tc.
- Including Tc in the effective pull: Tc cancels in T₁ − T₂, but it lowers the T₁ available from a fixed T_max, so it limits power at high speed.
- Mixing pulley diameter and radius in the length and angle formulas.
- Treating chain drives as slip-free and therefore constant-velocity; the average ratio is exact, but the instantaneous speed fluctuates.
For GATE PI
Expect the tension ratio for flat and V-belts, power from T₁ and T₂, centrifugal tension and the speed for maximum power, open and crossed belt angle of contact and length, speed ratio with slip, and sprocket pitch diameter or chain speed. Practise the e^(μθ) calculation with θ in radians and checking which pulley governs.
Quick check
- A flat belt has μ = 0.3 and θ = π rad. If T₂ = 100 N, what is T₁?
- At what fraction of the maximum tension is centrifugal tension when power is maximum?
- Why does a V-belt transmit more power than a flat belt for the same tensions?
- In which drive do both pulleys have the same angle of contact?
- What is the pitch diameter of a 20-tooth sprocket for a 12.7 mm pitch chain?
Answers: 1. about 256.6 N; 2. one third; 3. the wedge raises the normal force, so the effective friction coefficient becomes μ/sin α; 4. the crossed belt drive; 5. about 81.2 mm.
Interview questions
All Theory of Machines and Machine Design interview questionsTry answering each one aloud before you open it.
1.What is a belt drive and where is it commonly used?Concept
A belt drive is a mechanical system that uses a belt to transmit power between two rotating shafts. It is commonly used in applications like conveyor systems, automotive engines, and industrial machinery due to its simplicity and cost-effectiveness.
2.Explain the difference between flat belts and V-belts.Concept
A flat belt has a rectangular section and runs on a crowned pulley; it suits long centre distances and high speeds and is very efficient. A V-belt has a trapezoidal section that wedges into a grooved pulley, so the normal reaction rises by 1/sin α (α half the groove angle) and the tension ratio becomes e^(μθ/sin α). That lets a V-belt transmit more power for the same tension at short centre distances, though wedging and flexing make it slightly less efficient than a flat belt.
3.What are the advantages of using chain drives over belt drives?Concept
A chain gives a positive drive with no slip or creep, so the average speed ratio is exact. It carries higher loads at moderate speeds in a compact space, needs no initial tension (so lower bearing loads) and tolerates heat and moisture better than a belt. In return it needs lubrication and alignment, is noisier, and its instantaneous speed fluctuates because of chordal (polygon) action.
4.Why are idler pulleys used in belt drive systems?Application
Idler pulleys are used to maintain tension in the belt, guide the belt around obstacles, and increase the wrap angle around the drive pulleys. This helps in reducing belt slip and improving the efficiency of power transmission.
5.What happens if a belt drive is not properly aligned?Application
If a belt drive is not properly aligned, it can lead to increased wear and tear on the belt, reduced efficiency, and potential belt failure. Misalignment causes uneven load distribution, leading to premature failure of the belt and associated components.
6.How does the tension in a belt affect its performance?Application
Proper tension in a belt is crucial for optimal performance. If the tension is too low, the belt may slip, reducing efficiency and causing wear. If the tension is too high, it can lead to excessive stress on the belt and pulleys, resulting in premature failure.
7.Where are rope drives used, and why are they less common in modern machinery?Application
Rope drives use several fibre or wire ropes in grooved sheaves and were used to carry large power over long distances, for example in textile mills; wire ropes are still standard in hoists, cranes and lifts. For general power transmission they have largely been replaced by multiple V-belts, chains and individual electric motors, which are more compact, easier to maintain and do not need the large sheaves that rope bending life demands.
8.Calculate the speed of the driven pulley if the driver pulley has a diameter of 0.5 m, rotates at 300 RPM, and the driven pulley has a diameter of 1 m.Numerical
Using the formula for belt drives: N2 = (D1 * N1) / D2, where N1 = 300 RPM, D1 = 0.5 m, and D2 = 1 m. N2 = (0.5 * 300) / 1 = 150 RPM. The speed of the driven pulley is 150 RPM.
9.A chain drive system has a driving sprocket with 20 teeth and a driven sprocket with 40 teeth. If the driving sprocket rotates at 600 RPM, what is the speed of the driven sprocket?Numerical
The speed ratio is determined by the number of teeth: N2 = (T1 * N1) / T2, where T1 = 20, N1 = 600 RPM, and T2 = 40. N2 = (20 * 600) / 40 = 300 RPM. The speed of the driven sprocket is 300 RPM.
10.Explain the concept of slip in belt drives and how it affects performance.Concept
Slip is the bulk sliding of the belt over the pulley when friction cannot carry the required difference of tensions, i.e. when T₁/T₂ would have to exceed e^(μθ). It is expressed as a percentage and reduces the driven speed, so N₂/N₁ = (d₁/d₂)(1 − s/100). Excessive slip wastes power as heat and wears the belt. It is different from creep, the small unavoidable relative motion caused by unequal stretching of the tight and slack sides.
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