Vacuum measurement: McLeod, Pirani and ionisation gauges

Vacuum ranges and the McLeod (compression), Pirani and thermocouple (thermal conductivity) and hot- and cold-cathode ionisation gauges, with worked numericals.

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Why it matters

Vacuum is used in freeze drying, distillation of heat-sensitive products, vacuum furnaces, thin-film coating, electron microscopes and semiconductor fabrication. Below a few hundred pascals, elastic gauges and manometers lose sensitivity, so plants rely on gauges that measure a property of the rarefied gas: its compressibility (McLeod), its thermal conductivity (Pirani, thermocouple gauge) or how many ions it produces (ionisation gauges). Choosing the right gauge for the range, and knowing which ones depend on the gas composition, is a routine design decision.

Key ideas

Vacuum ranges (approximate). Rough vacuum: atmospheric down to about 100 Pa; medium vacuum: 100 Pa to 0.1 Pa; high vacuum: 0.1 Pa to about 10⁻⁵ Pa; ultra-high vacuum: below about 10⁻⁵ Pa. 1 Torr ≈ 1 mm Hg ≈ 133.3 Pa; 1 mbar = 100 Pa.

McLeod gauge (compression gauge).

  • A known volume V of gas at the unknown pressure p is trapped in a glass bulb by raising mercury, then compressed into a sealed capillary of bore area a. Boyle's law (isothermal) gives the original pressure from the compressed one.
  • Square-law method: mercury in the open reference capillary is raised until it is level with the top of the sealed capillary. The trapped gas column then has length h, and its pressure exceeds p by ρgh. This gives p ≈ ρ·g·a·h²/V, so the scale is non-linear (square law).
  • It is an absolute gauge: the calibration follows from dimensions only, independent of gas type, so it is used to calibrate Pirani and ionisation gauges.
  • Limitations: intermittent (not continuous) reading, mercury handling, and it does not read condensable vapours correctly, because vapours condense when compressed and do not obey Boyle's law. Typical range from about 10 Pa down to about 10⁻³ Pa, depending on bulb and capillary size.

Thermal-conductivity gauges (Pirani and thermocouple).

  • A heated filament loses heat by conduction through the gas, by radiation and through its supports. At low pressure (when the molecular mean free path is comparable to the filament-to-wall gap) the gas conduction is roughly proportional to pressure.
  • Pirani: the filament (platinum or tungsten) forms one arm of a Wheatstone bridge. As pressure falls, less heat is conducted away, the filament runs hotter and its resistance rises, unbalancing the bridge. In the constant-temperature version the bridge voltage is servoed to keep the filament resistance fixed, and the heating power is the measure of pressure. A sealed, evacuated compensating filament in the adjacent arm cancels ambient temperature changes.
  • Thermocouple gauge: constant heater current; a thermocouple welded to the heater reads its temperature, which rises as pressure falls.
  • Useful range roughly 0.1 Pa to 1 kPa. Above this the gas conductivity becomes nearly independent of pressure; below it radiation and end losses swamp the gas conduction.
  • The reading depends on the gas, because thermal conductivity differs (hydrogen and helium conduct far better than air). Readings for other gases need correction factors or calibration.

Ionisation gauges.

  • Hot-cathode (triode or Bayard–Alpert): electrons from a heated filament are accelerated towards a positive grid; they ionise gas molecules, and the positive ions are collected by a negative collector. The ion current is proportional to the molecular density: Ii = S·Ie·p. The Bayard–Alpert design uses a fine wire collector inside the grid to reduce the X-ray limit and reaches about 10⁻⁸ Pa or lower.
  • Cold-cathode (Penning): a high voltage discharge in a magnetic field; no filament to burn out, but less accurate.
  • Range about 10⁻¹ Pa downwards; above that the filament can burn out and the current is no longer linear. The sensitivity S depends on gas type (ionisation cross-section).

Choosing a gauge. Systems usually carry two gauges: a Pirani for rough/medium vacuum and an ionisation gauge switched on only after the Pirani shows the pressure is low enough. A McLeod (or a capacitance diaphragm gauge, which is gas-independent) serves as the reference.

Formulas

p·V = (p + ρ·g·h)·a·h (McLeod, square-law, Boyle's law on the trapped gas)

p = ρ·g·a·h² / (V − a·h) ≈ ρ·g·a·h² / V (McLeod, when a·h ≪ V)

Ii = S·Ie·p (hot-cathode ionisation gauge)

P_el = P₀ + C·p (Pirani in its linear low-pressure region; idealised)

Symbols: p = unknown pressure (Pa); V = volume trapped (bulb plus capillary) (m³); a = bore area of the sealed capillary (m²); h = length of compressed gas column = difference in mercury levels (m); ρ = density of mercury (13 600 kg/m³); g = 9.81 m/s²; Ii = ion current (A); Ie = electron emission current (A); S = gauge sensitivity (Pa⁻¹), gas-dependent; P_el = electrical power to hold the filament at constant temperature (W); P₀ = radiation and end losses (W); C = constant from calibration (W/Pa).

Worked examples

Example 1 (standard): ionisation gauge. Given: Bayard–Alpert gauge, sensitivity for nitrogen S = 0.075 Pa⁻¹ (about 10 Torr⁻¹), emission current Ie = 4 mA, ion current Ii = 3 nA.

  1. p = Ii / (S·Ie).
  2. S·Ie = 0.075 × 4 × 10⁻³ = 3.0 × 10⁻⁴ A/Pa.
  3. p = 3 × 10⁻⁹ / 3.0 × 10⁻⁴ = 1.0 × 10⁻⁵ Pa.
  4. Answer: p = 1.0 × 10⁻⁵ Pa (high vacuum). For a different gas, S changes and the reading must be corrected.

Example 2 (GATE level): McLeod gauge. Given: bulb plus capillary volume V = 100 cm³, sealed capillary bore 1.0 mm, square-law reading h = 20 mm of mercury, ρ = 13 600 kg/m³.

  1. a = π·d²/4 = π × (1.0 × 10⁻³)² / 4 = 7.854 × 10⁻⁷ m².
  2. a·h = 7.854 × 10⁻⁷ × 0.020 = 1.571 × 10⁻⁸ m³, which is negligible against V = 1.0 × 10⁻⁴ m³.
  3. p ≈ ρ·g·a·h² / V = 13 600 × 9.81 × 7.854 × 10⁻⁷ × (0.020)² / 1.0 × 10⁻⁴.
  4. ρ·g·h = 13 600 × 9.81 × 0.020 = 2668.3 Pa; compression ratio a·h/V = 1.571 × 10⁻⁴.
  5. p = 2668.3 × 1.571 × 10⁻⁴ = 0.419 Pa.
  6. Answer: p ≈ 0.42 Pa. Note the gas was compressed about 6400 times, which is why the gauge can read such low pressures with a mercury column.

Example 3 (Pirani, idealised linear region). A constant-temperature Pirani needs 10.0 mW at very high vacuum (P₀) and 14.0 mW at a calibration pressure of 1.0 Pa. Then C = (14.0 − 10.0)/1.0 = 4.0 mW/Pa. At 12.0 mW: p = (12.0 − 10.0)/4.0 = 0.50 Pa. Real Pirani curves are only linear near the low end, so manufacturers supply full calibration curves.

Common mistakes

  • Using the McLeod gauge on water vapour or solvent vapour: the vapour condenses on compression and the gauge reads low.
  • Forgetting that the McLeod square-law scale is non-linear (p ∝ h²).
  • Applying an air-calibrated Pirani or ionisation reading directly to helium, hydrogen or argon without the gas correction factor.
  • Switching on a hot-cathode ionisation gauge at rough vacuum; the filament oxidises or burns out.
  • Mixing Torr, mbar and Pa: 1 Torr = 133.3 Pa, 1 mbar = 100 Pa.
  • Thinking a Pirani wire cools as vacuum improves; it gets hotter because less heat is conducted away.

For GATE IN

Questions are mostly conceptual: which gauge suits which range, which are absolute and gas-independent (McLeod, capacitance diaphragm), which property each senses, and why a bridge with a compensating element is used in the Pirani gauge. Numericals use Boyle's law in the McLeod gauge (often the square-law relation) and the ion-current relation. Practise unit conversion between Pa, mbar and Torr.

Quick check

  1. Which vacuum gauge is absolute and used to calibrate others?
  2. Why does a Pirani gauge lose sensitivity above about 1 kPa?
  3. In a McLeod gauge, how does p scale with the reading h in the square-law method?
  4. An ionisation gauge has S = 0.1 Pa⁻¹ and Ie = 2 mA. What pressure gives Ii = 2 nA?
  5. Why is the McLeod gauge unsuitable for water vapour?

Answers: 1. McLeod gauge. 2. Gas conductivity becomes nearly independent of pressure. 3. p ∝ h². 4. 1 × 10⁻⁵ Pa. 5. The vapour condenses on compression and does not follow Boyle's law.

Try answering each one aloud before you open it.

  1. 1.What is a McLeod gauge and how does it work?Concept

    A McLeod gauge is a compression vacuum gauge. Raising mercury traps a known volume V of gas at the unknown pressure p and compresses it into a sealed capillary of bore area a; Boyle's law then relates the higher, measurable pressure of the compressed gas back to p. In the square-law method p ≈ ρ·g·a·h²/V, where h is the length of the compressed column. Because the calibration follows from dimensions alone and is independent of gas type, it is an absolute gauge used to calibrate Pirani and ionisation gauges, typically from about 10 Pa down to about 10⁻³ Pa.

  2. 2.Explain the working principle of a Pirani gauge.Concept

    A Pirani gauge measures vacuum pressure by determining the thermal conductivity of the gas. It consists of a heated wire whose resistance changes with temperature. As the pressure decreases, the gas density decreases, leading to less heat being conducted away from the wire. This causes the wire to heat up and its resistance to change, which is measured to determine the pressure. Pirani gauges are typically used for pressures in the range of 10^-3 to 10 Torr.

  3. 3.Describe the operation of an ionization gauge.Concept

    An ionization gauge measures vacuum pressure by ionizing gas molecules and measuring the resulting ion current. It consists of a filament that emits electrons, which collide with gas molecules to create ions. These ions are collected by an electrode, and the resulting current is proportional to the gas pressure. Ionization gauges are used for very low pressures, typically in the range of 10^-3 to 10^-9 Torr.

  4. 4.Why is a McLeod gauge not suitable for continuous pressure monitoring?Application

    Each reading needs a manual cycle: mercury must be raised to trap and compress a gas sample and then lowered again, so the gauge gives intermittent spot readings, not a continuous electrical signal for control or logging. It also uses mercury, is fragile glass, and cannot read condensable vapours such as water, because they condense on compression and do not obey Boyle's law. It is therefore kept as a reference standard, while Pirani or ionisation gauges do the continuous monitoring.

  5. 5.What are the advantages of using a Pirani gauge over a McLeod gauge?Application

    A Pirani gauge gives a continuous electrical output that can be displayed, logged or used for interlocks, responds quickly, uses no mercury and is compact and cheap. It also reads in the presence of condensable vapours, which a McLeod gauge cannot. Its drawbacks are that it is not absolute: the reading depends on the thermal conductivity of the gas, so it must be calibrated (often against a McLeod gauge) and corrected for gases other than air or nitrogen, and its useful range is limited to roughly 0.1 Pa to 1 kPa.

  6. 6.What happens if the filament in a Pirani gauge breaks?Application

    If the filament in a Pirani gauge breaks, the gauge will no longer be able to measure pressure accurately. The filament is essential for heating and measuring the thermal conductivity of the gas. A broken filament means there will be no change in resistance to measure, rendering the gauge inoperative until the filament is replaced.

  7. 7.How does the presence of different gases affect the readings of a Pirani gauge?Application

    The presence of different gases affects the readings of a Pirani gauge because different gases have different thermal conductivities. The gauge is calibrated for a specific gas, usually nitrogen or air. If a different gas is present, the thermal conductivity will differ, leading to inaccurate pressure readings unless the gauge is recalibrated for that specific gas.

  8. 8.Calculate the pressure indicated by a McLeod gauge if the initial volume of gas is 100 cm³ and the final volume after compression is 1 cm³, with a final pressure of 1000 Torr.Numerical

    The pressure indicated by a McLeod gauge can be calculated using Boyle's Law, which states that P1·V1 = P2·V2. Here, P1 is the initial pressure, V1 is the initial volume, P2 is the final pressure, and V2 is the final volume. Rearranging gives P1 = (P2·V2) / V1. Substituting the given values: P1 = (1000 Torr · 1 cm³) / 100 cm³ = 10 Torr.

  9. 9.Why are ionization gauges preferred for ultra-high vacuum applications?Application

    Ionization gauges are preferred for ultra-high vacuum applications because they can measure very low pressures, down to 10^-9 Torr or lower. They are highly sensitive and can detect the small number of gas molecules present in such environments. Their ability to provide accurate and reliable measurements at these low pressures makes them ideal for applications like semiconductor manufacturing and surface science research.

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