Single-phase induction motors
Why a single-phase motor is not self-starting, double-revolving-field theory and equivalent circuit, and split-phase, capacitor and shaded-pole motors.
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Why it matters
Fans, pumps, compressors, washing machines, small blowers and laboratory equipment run on single-phase induction motors because homes, offices and small workshops have only a single-phase supply. Knowing why they are not self-starting, and how each starting arrangement fixes that, is what you need to choose, troubleshoot (the classic failed fan capacitor) or replace one.
Key ideas
A single winding gives a pulsating field. One stator winding fed with single-phase AC produces a field that alternates along a fixed axis; it does not rotate. At standstill it produces no net torque, so the motor hums but does not start. Once spun in either direction, however, it keeps running in that direction.
Double-revolving-field theory. A pulsating field of peak Φm is equivalent to two fields of Φm/2 each rotating in opposite directions at synchronous speed Ns.
- If the rotor runs at speed N in the forward direction, its slip with respect to the forward field is s = (Ns − N)/Ns, and with respect to the backward field it is (Ns + N)/Ns = 2 − s.
- Each field produces a torque–slip curve like a three-phase motor. At standstill (s = 1 for both) the two torques are equal and opposite, so net starting torque is zero.
- When the rotor turns forward, the forward torque dominates and the motor accelerates. The backward field induces rotor currents at frequency (2 − s)·f (close to 2f), which cause extra rotor loss and a double-frequency torque pulsation. Hence single-phase motors are noisier, less efficient and have a lower power factor than three-phase motors of the same size, and maximum torque is reached at a speed lower than in the equivalent three-phase motor.
- The equivalent circuit splits the rotor into a forward half (0.5·R2'/s, 0.5·X2', 0.5·Xm) and a backward half (0.5·R2'/(2 − s), 0.5·X2', 0.5·Xm) in series. Net air-gap power = Pf − Pb; torque = (Pf − Pb)/ωs.
- (The cross-field theory gives the same results by a different argument.)
Making it self-starting: a second winding displaced 90° in space carrying a current displaced in time — together the two windings produce a (roughly elliptical) rotating field.
- Split-phase (resistance-start): auxiliary winding of fewer turns of thinner wire, so higher R/X ratio; its current leads the main-winding current by about 25–30°. Moderate starting torque; a centrifugal switch disconnects the auxiliary winding at about 70–80 % of synchronous speed. Used in fans, small pumps, washing machines.
- Capacitor-start: a capacitor (electrolytic, short-duty) in series with the auxiliary winding brings its current nearly 90° ahead of the main current — high starting torque. Centrifugal switch removes it. Used for compressors, refrigerators, pumps.
- Capacitor-start capacitor-run: a large start capacitor plus a smaller run capacitor that stays in circuit: good starting torque, better running power factor and efficiency, quieter.
- Permanent-split capacitor (PSC): one run capacitor permanently in circuit, no switch; modest starting torque; ceiling fans and blowers. A failed fan capacitor gives exactly the symptom described above: it hums but turns only if pushed.
- Shaded-pole: part of each salient pole is surrounded by a copper shading ring; induced ring current delays the flux in the shaded part, giving a field that sweeps from the unshaded to the shaded part. Very cheap and robust; very low starting torque and efficiency; direction fixed by construction. Small fans, hair dryers.
- Reversing a split-phase or capacitor motor: reverse the connections of either the main or the auxiliary winding (not both).
Formulas
Ns = 120·f / P— synchronous speed (rpm).s_f = s = (Ns − N)/Ns ; s_b = 2 − s— slips with respect to forward and backward fields.f_rotor,f = s·f ; f_rotor,b = (2 − s)·f— rotor current frequencies (Hz).Zf = 0.5·[jXm ∥ (R2'/s + jX2')] ; Zb = 0.5·[jXm ∥ (R2'/(2 − s) + jX2')]— forward and backward impedances (Ω).Pf = I²·Re(Zf) ; Pb = I²·Re(Zb)— forward and backward air-gap powers (W).T = (Pf − Pb) / ωs ; Pm = (1 − s)·(Pf − Pb)— net torque (N·m) and gross mechanical power (W).
Worked examples
Example 1 (standard): slips and rotor frequencies. Given: 4-pole, 50 Hz single-phase induction motor running at 1440 rpm.
- Ns = 120 × 50/4 = 1500 rpm.
- Forward slip s = (1500 − 1440)/1500 = 0.04; backward slip = 2 − 0.04 = 1.96.
- Rotor current frequency due to forward field = 0.04 × 50 = 2 Hz; due to backward field = 1.96 × 50 = 98 Hz.
Example 2 (GATE level): equivalent-circuit performance. Given: 230 V, 50 Hz, 4-pole single-phase motor, main winding only (running). R1 = 2 Ω, X1 = 3 Ω, R2' = 4 Ω, X2' = 2 Ω, Xm = 60 Ω; slip 0.05. Neglect core loss.
- R2'/s = 80 Ω; R2'/(2 − s) = 4/1.95 = 2.05 Ω.
- Zf = 0.5 × [j60 ∥ (80 + j2)] = 14.06 + j19.11 Ω; Zb = 0.5 × [j60 ∥ (2.05 + j2)] = 0.96 + j1.00 Ω.
- Total Z = (2 + j3) + Zf + Zb = 17.02 + j23.11 Ω, |Z| = 28.70 Ω.
- Current I = 230/28.70 = 8.02 A at power factor 17.02/28.70 = 0.593 lagging.
- Pf = 8.02² × 14.06 = 903 W; Pb = 8.02² × 0.96 = 61.6 W.
- Torque T = (903 − 61.6)/157.08 = 5.36 N·m; gross mechanical power = 0.95 × 841.4 = 799 W.
Common mistakes
- Saying the single-phase field "rotates slowly" — it only pulsates; rotation comes from the second winding.
- Using s instead of 2 − s for the backward field.
- Forgetting the factor 0.5 on each half of the equivalent circuit.
- Thinking a capacitor-start motor stops if its capacitor fails while running; it keeps running on the main winding but will not restart.
- Reversing both windings to change direction (that changes nothing).
- Expecting a shaded-pole motor to be reversible without mechanical changes.
For GATE IN
Expect conceptual MCQs (why not self-starting, which motor has the highest starting torque, what the centrifugal switch does, phase angle in split-phase versus capacitor motors) and numericals on forward/backward slip, rotor frequencies and torque from the double-revolving-field equivalent circuit.
Quick check
- A 2-pole, 50 Hz single-phase motor runs at 2850 rpm. What is the backward slip?
- Which single-phase motor has the lowest starting torque?
- Why does a capacitor give more starting torque than a split-phase resistance?
- At what frequency do rotor currents due to the backward field flow at slip s?
Answers: 1. s = 0.05, backward slip = 1.95. 2. Shaded-pole. 3. It makes the auxiliary current lead the main current by nearly 90°, giving a near-circular rotating field. 4. (2 − s)·f.
Interview questions
All Electrical Machines interview questionsTry answering each one aloud before you open it.
1.What is a single-phase induction motor?Concept
A single-phase induction motor is an AC motor that operates on a single-phase power supply. It consists of a stator with a single-phase winding and a rotor, typically a squirrel cage type. These motors are commonly used in household appliances and small machinery due to their simplicity and cost-effectiveness.
2.Explain the working principle of a single-phase induction motor.Concept
A single stator winding on single-phase AC produces a pulsating, not rotating, field. By double-revolving-field theory this equals two half-amplitude fields rotating in opposite directions; at standstill their torques cancel, so there is no starting torque. Once the rotor turns, the field rotating in the same direction produces more torque than the opposing one, so the motor accelerates to near synchronous speed. To start it, an auxiliary winding displaced 90° in space with a phase-shifted current (via resistance or a capacitor) creates a rotating field.
3.Why is a single-phase induction motor not self-starting?Concept
A single-phase induction motor is not self-starting because the single-phase supply produces a pulsating magnetic field rather than a rotating one. This pulsating field does not create the necessary torque to start the rotor. To overcome this, an auxiliary winding or a starting capacitor is used to create a phase difference, generating a rotating magnetic field to start the motor.
4.What are the common starting methods for single-phase induction motors?Concept
Common starting methods for single-phase induction motors include the split-phase method, capacitor-start method, and shaded-pole method. The split-phase method uses an auxiliary winding with a higher resistance to create a phase difference. The capacitor-start method uses a capacitor in series with the auxiliary winding to improve starting torque. The shaded-pole method uses a shaded coil to create a rotating magnetic field.
5.Explain the role of a capacitor in a capacitor-start single-phase induction motor.Concept
In a capacitor-start single-phase induction motor, the capacitor is connected in series with the auxiliary winding. It creates a phase shift between the current in the main winding and the auxiliary winding, producing a rotating magnetic field. This phase shift enhances the starting torque, allowing the motor to start effectively.
6.What happens if the capacitor in a capacitor-start motor fails?Application
Without the capacitor the auxiliary current is not phase-shifted, so at standstill the motor has essentially no starting torque: it hums, draws a high current and will overheat or trip its overload if left energised. If it fails while the motor is already running, the motor keeps running on the main winding but will not restart. A ceiling fan that turns only when pushed by hand shows the same fault in its run capacitor.
7.Why are single-phase induction motors commonly used in household appliances?Application
Single-phase induction motors are commonly used in household appliances because they are simple, reliable, and cost-effective. They can operate directly from the single-phase AC supply available in homes. Their compact size and ease of maintenance make them suitable for applications like fans, refrigerators, and washing machines.
8.What is the effect of increasing the load on a single-phase induction motor?Application
Increasing the load on a single-phase induction motor will cause the motor to draw more current to maintain its speed. If the load exceeds the motor's rated capacity, it may overheat, leading to potential damage. The motor's efficiency may also decrease as it operates under higher load conditions.
9.A 1.5 kW (output), 230 V single-phase induction motor has a full-load power factor of 0.8 and efficiency of 80 %. Estimate its full-load current, and comment on its starting current.Numerical
Input power = 1500/0.8 = 1875 W, so full-load current I = 1875/(230 × 0.8) = 10.2 A. The starting (locked-rotor) current is not obtained from this formula: at standstill the motor behaves like a short-circuited transformer and draws several times (typically 4–7 times) full-load current, so the supply wiring and protection must allow for it.
10.A single-phase induction motor has a slip of 5% at full load. If the synchronous speed is 1500 RPM, what is the rotor speed at full load?Numerical
The rotor speed can be calculated using the formula: Rotor Speed = Synchronous Speed × (1 - Slip). Here, Synchronous Speed = 1500 RPM and Slip = 5% = 0.05. So, Rotor Speed = 1500 × (1 - 0.05) = 1425 RPM. Therefore, the rotor speed at full load is 1425 RPM.
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