Ride comfort: quarter-car model and human response to vibration

The two-degree-of-freedom quarter-car model: ride rate, body and wheel-hop frequencies, damping ratio, transmissibility and isolation, road wavelength input, and how humans respond to vibration (ISO 2631 sensitivities and motion sickness).

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Why it matters

Ride comfort is one of the first things a customer notices and one of the hardest to engineer, because the suspension must also keep the tyres pressed on the road and fit inside limited suspension travel. On Indian roads, with speed breakers, potholes and long stretches of broken surface, poor ride causes fatigue, back problems in commercial drivers and damage to cargo. The quarter-car model is the standard first tool for choosing spring rates and damping.

Key ideas

The quarter-car model. One corner of the vehicle is represented by two masses:

  • the sprung mass m_s — the share of body, passengers and load carried by that corner's spring;
  • the unsprung mass m_u — wheel, tyre, hub, brake and part of the suspension links and spring. The suspension spring k_s and damper c_s act between them; the tyre is modelled as a stiff spring k_t (its damping is small) between the unsprung mass and the road. The road profile z_r(t) is the input. This gives two degrees of freedom and two natural modes.

Body (bounce) mode. The sprung mass bounces on the suspension spring and tyre in series. The combined ride rate K_R = k_s·k_t/(k_s + k_t) is slightly less than k_s. Passenger cars aim for a body natural frequency of about 1.0–1.5 Hz (sports cars higher, about 1.5–2 Hz) — close to the frequency of walking, which people find natural.

Wheel-hop mode. The unsprung mass vibrates between the suspension spring and the much stiffer tyre at about 10–15 Hz. Large wheel-hop motion means large swings in tyre load, so less grip — this is the road-holding problem.

Damping. The damping ratio ζ = c_s/(2√(K·m_s)) is typically 0.2–0.4 for comfort-oriented cars. Low damping lets the body float and resonate; high damping makes the car feel harsh because more of the road input is transmitted above resonance. Real dampers are tuned with different rates in bump and rebound.

Transmissibility and isolation. For a base-excited single-degree system (body on ride rate), the ratio of body to road amplitude is the transmissibility T. It exceeds 1 near resonance (r = f/f_n ≈ 1) and falls below 1 only when r > √2 — isolation. Adding damping reduces the resonant peak but worsens isolation at high frequency: the central compromise of passive suspension design.

Road input. A road with wavelength λ driven over at speed V excites frequency f = V/λ. Long wavelengths excite body bounce; short ones excite wheel hop and are felt as harshness. Real roads are random, described by a power spectral density.

Design trade-offs. A softer spring lowers body frequency and improves comfort but needs more suspension travel (rattle space) and allows more roll and pitch. A lighter unsprung mass (alloy wheels, aluminium knuckles) improves both comfort and road holding — hence interest in a high sprung-to-unsprung mass ratio (about 8–12 for cars). Active and semi-active suspensions relax the compromise.

Human response to vibration. Sensitivity depends on frequency, direction, amplitude, duration and posture. ISO 2631 (the reference standard; use its weighting tables for actual values) shows that seated people are most sensitive to vertical vibration at about 4–8 Hz (resonance of the abdominal organs and spine) and to horizontal vibration at about 1–2 Hz. Very low frequencies, about 0.1–0.5 Hz, cause motion sickness. Comfort is judged from the frequency-weighted r.m.s. acceleration (m/s²); shocks are better captured by the vibration dose value (VDV). Weighted r.m.s. values below about 0.3 m/s² are generally not uncomfortable, while values above about 1–2 m/s² are very uncomfortable (check the exact bands in the standard).

Pitch and the Olley criteria. Front and rear ends meet a bump at different times. Making the front ride frequency slightly lower than the rear (by roughly 10–20%) lets the rear "catch up", turning pitch into flatter bounce.

Formulas

K_R = k_s·k_t / (k_s + k_t) — ride rate (N/m); k_s suspension spring rate at the wheel, k_t tyre vertical stiffness.

f_b = (1/2π)·√(K_R / m_s) — body (bounce) natural frequency (Hz); m_s sprung mass per corner (kg).

f_h = (1/2π)·√((k_s + k_t) / m_u) — wheel-hop frequency (Hz); m_u unsprung mass per corner (kg).

ζ = c_s / (2·√(K_R·m_s)) — damping ratio of the body mode (dimensionless); c_s in N·s/m.

f = V / λ — excitation frequency (Hz) from a road wavelength λ (m) at speed V (m/s).

T = √[(1 + (2ζr)²) / ((1 − r²)² + (2ζr)²)] — displacement transmissibility for base excitation; r = f/f_n.

a_peak = (2πf)²·X — peak acceleration (m/s²) for a harmonic motion of amplitude X (m).

F_d = c_s·v, F_s = k_s·x — damper and spring forces (N), v relative velocity (m/s), x deflection (m).

Worked examples

Example 1 (standard). One corner of a car has m_s = 300 kg, m_u = 40 kg, k_s = 22 000 N/m, k_t = 200 000 N/m, c_s = 1800 N·s/m. Find the ride rate, body and wheel-hop frequencies and damping ratio.

  1. K_R = k_s·k_t/(k_s + k_t) = 22 000 × 200 000/222 000 = 19 820 N/m.
  2. f_b = (1/2π)√(K_R/m_s) = (1/2π)√(66.07) = 8.128/6.283 = 1.29 Hz (spring alone would give 1.36 Hz).
  3. f_h = (1/2π)√((k_s + k_t)/m_u) = (1/2π)√(5550) = 74.50/6.283 = 11.9 Hz.
  4. ζ = c_s/(2√(K_R·m_s)) = 1800/(2√(5.946×10⁶)) = 1800/4877 = 0.37.

Example 2 (GATE level). The same car (treat the body as a single-degree system on K_R with ζ = 0.37) drives over a road with a sinusoidal profile of wavelength 10 m and amplitude 20 mm. (a) At what speed does body resonance occur? (b) Find the body amplitude and peak body acceleration at 54 km/h.

  1. Resonance when V/λ = f_b: V = 1.294 × 10 = 12.9 m/s ≈ 46.6 km/h.
  2. At 54 km/h, V = 15 m/s, so f = V/λ = 1.5 Hz and r = 1.5/1.294 = 1.160.
  3. 2ζr = 0.856; 1 − r² = −0.3445. T = √[(1 + 0.733)/(0.1187 + 0.733)] = √(1.733/0.852) = 1.43.
  4. Body amplitude X = 1.43 × 20 = 28.5 mm — still amplified, because r < √2.
  5. a_peak = (2πf)²·X = (9.425)² × 0.0285 = 2.53 m/s² — very uncomfortable; a softer spring or higher speed (r > √2) would isolate.

Common mistakes

  • Using the full vehicle mass instead of the sprung mass per corner.
  • Ignoring the tyre spring in series, which overestimates body frequency.
  • Assuming more damping always improves comfort; it helps only near resonance.
  • Expecting isolation at any r > 1. Transmissibility falls below 1 only for r > √2.
  • Confusing natural frequency in rad/s with Hz (divide ω by 2π).
  • Quoting "1–2 Hz causes motion sickness". Motion sickness is linked to about 0.1–0.5 Hz; 4–8 Hz vertical is the most sensitive band for comfort.

For GATE ME

Expect natural-frequency and damping-ratio calculations, transmissibility from road wavelength and speed, speed at resonance, and conceptual questions on sprung/unsprung mass, isolation and human vibration sensitivity. This topic overlaps heavily with base excitation in vibrations, so practise those formulas in vehicle form.

Quick check

  1. k_s = 20 000 N/m, m_s = 320 kg (ignore tyre). Body frequency?
  2. At which r does transmissibility fall below 1?
  3. Which frequency band of vertical vibration are seated humans most sensitive to?
  4. A car at 20 m/s crosses ridges every 5 m. Excitation frequency?
  5. Why do engineers try to reduce unsprung mass?

Answers: 1. (1/2π)√62.5 = 1.26 Hz. 2. r > √2 ≈ 1.41. 3. About 4–8 Hz. 4. 4 Hz. 5. It improves road holding and reduces harshness transmitted to the body.

Try answering each one aloud before you open it.

  1. 1.What is a quarter-car model in vehicle dynamics?Concept

    The quarter-car model represents one corner of the vehicle as two masses: the sprung mass, the body share carried by that corner, and the unsprung mass, which is the wheel, tyre, hub, brake and part of the links. The suspension spring and damper act between them, and the tyre acts as a stiff spring between the unsprung mass and the road profile. It has two modes, body bounce at about 1–1.5 Hz and wheel hop at about 10–15 Hz, and is used to trade off ride comfort (body acceleration), road holding (tyre load variation) and suspension travel when choosing spring and damper rates. It ignores pitch, roll and coupling between corners.

  2. 2.Explain the importance of ride comfort in vehicle dynamics.Concept

    Ride comfort is crucial in vehicle dynamics as it directly affects the passenger experience. It involves minimizing vibrations and shocks transmitted to the vehicle occupants from road irregularities. Good ride comfort enhances passenger satisfaction, reduces driver fatigue, and can improve vehicle safety by maintaining better control over the vehicle.

  3. 3.How does the quarter-car model help in understanding human response to vibration?Concept

    The quarter-car model predicts the body acceleration and its frequency content for a given road input and speed. That spectrum is then weighted according to human sensitivity, as in ISO 2631, which shows seated people are most sensitive to vertical vibration around 4–8 Hz and to horizontal vibration around 1–2 Hz, while 0.1–0.5 Hz motion causes motion sickness. Engineers therefore put the body bounce frequency near 1–1.5 Hz, away from these bands, and judge comfort by the frequency-weighted r.m.s. acceleration.

  4. 4.Why is the spring-damper system used in the quarter-car model?Application

    The spring-damper system is used in the quarter-car model to simulate the suspension system's ability to absorb and dissipate energy from road irregularities. The spring represents the elastic component that stores energy, while the damper represents the dissipative component that reduces oscillations. Together, they help in controlling the vertical motion of the vehicle, improving ride comfort and stability.

  5. 5.What happens if the damping ratio in a quarter-car model is too low?Application

    If the damping ratio in a quarter-car model is too low, the suspension system will not effectively dissipate energy from road-induced vibrations. This can lead to excessive oscillations and a bouncy ride, reducing ride comfort and potentially affecting vehicle handling and safety. Passengers may experience discomfort due to increased vibrations.

  6. 6.Describe how road surface irregularities affect the quarter-car model.Concept

    Road surface irregularities, such as bumps and potholes, introduce vertical displacements to the wheel in the quarter-car model. These displacements cause the suspension system to compress and extend, generating forces that affect the vehicle's vertical motion. The model helps in analyzing how these forces are transmitted to the vehicle body and ultimately to the passengers, influencing ride comfort.

  7. 7.What are the roles of the sprung and unsprung masses in the quarter-car model?Concept

    The sprung mass, together with the ride rate, sets the body bounce frequency f = (1/2π)√(K/m_s) and how much road input reaches the occupants. The unsprung mass, between the suspension spring and the much stiffer tyre, sets the wheel-hop frequency of about 10–15 Hz and the dynamic tyre-load variation that governs road holding. A high ratio of sprung to unsprung mass, about 8–12 for cars, gives better comfort and grip, which is why designers use alloy wheels and aluminium suspension parts to cut unsprung mass.

  8. 8.How can engineers improve ride comfort using the quarter-car model?Application

    The model shows three competing targets: body acceleration for comfort, dynamic tyre load for road holding, and suspension deflection for rattle space. Engineers lower the spring rate to bring the body frequency to about 1–1.5 Hz as far as the available travel and roll stiffness allow, choose damping around ζ ≈ 0.2–0.4 as a compromise between resonance control and high-frequency harshness, and reduce unsprung mass. When the passive compromise is not good enough, the model is used to design semi-active (variable-damper) or active suspension control.

  9. 9.Calculate the natural frequency of a quarter-car model with a mass of 250 kg and a spring stiffness of 15,000 N/m.Numerical

    The natural frequency (f_n) can be calculated using the formula: f_n = (1/2π) * √(k/m), where k is the spring stiffness and m is the mass. Substituting the given values: f_n = (1/2π) * √(15000/250) = (1/2π) * √60 ≈ 1.23 Hz.

  10. 10.A quarter-car model has a damping coefficient of 1,200 Ns/m and a critical damping coefficient of 2,400 Ns/m. What is the damping ratio?Numerical

    The damping ratio (ζ) is calculated as the ratio of the damping coefficient (c) to the critical damping coefficient (c_c): ζ = c/c_c. Substituting the given values: ζ = 1200/2400 = 0.5.

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