Elementary flows: uniform flow, source, sink, doublet and vortex
Potential and stream functions of uniform flow, source, sink, doublet and point vortex, and how superposing them builds body shapes.
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Why it matters
Laplace's equation is linear, so a handful of simple solutions — uniform flow, source, sink, doublet and vortex — can be added together to build the flow past a cylinder, a Rankine body, a lifting airfoil or a whole wing (panel and vortex-lattice methods). Knowing their φ, ψ and velocity fields by heart is the toolkit for the rest of this subject.
Key ideas
All the elementary flows below are 2-D, incompressible and irrotational (except at a singular point), so each satisfies ∇²φ = 0 and ∇²ψ = 0. Polar coordinates (r, θ) are measured from the singularity, θ anticlockwise from the +x axis. The sign conventions follow Anderson's Fundamentals of Aerodynamics; some Indian texts absorb the 2π into the strength or use the opposite sign for vortex circulation — always check the convention of the question.
Uniform flow. Velocity V∞ along +x everywhere. Streamlines are horizontal lines, equipotentials vertical lines. Circulation round any closed curve is zero.
Source and sink. Purely radial flow from (source) or into (sink) a point. Strength Λ is the volume flow per unit depth (m²/s); Λ > 0 source, Λ < 0 sink. V_r = Λ/(2πr) falls off as 1/r; the point r = 0 is singular (infinite velocity), so it must lie inside a body or outside the flow region of interest. Streamlines are radial lines; equipotentials are circles.
Doublet. A source and an equal sink brought together (separation l → 0) while κ = l·Λ is held constant. Streamlines are circles passing through the doublet point, tangent to the x-axis there. On its own a doublet looks nothing like a body; added to a uniform stream it produces the flow past a circular cylinder (next topic).
Point vortex. Purely circumferential flow, V_θ = −Γ/(2πr) with Γ positive for clockwise rotation (Anderson's convention, chosen so that positive Γ gives positive lift later). Streamlines are circles, equipotentials radial lines. The flow is irrotational everywhere except at r = 0, where the vorticity is concentrated; the circulation round any curve enclosing the origin is Γ, and round any curve not enclosing it is zero. Real vortices have a viscous core of finite size (Rankine vortex model).
Superposition examples.
- Uniform flow + source → Rankine half-body: a stagnation point upstream of the source at distance Λ/(2πV∞); the dividing streamline ψ = Λ/2 is a semi-infinite body whose width tends to Λ/V∞ far downstream.
- Uniform flow + source + equal sink downstream → Rankine oval (closed body).
- Uniform flow + doublet → circular cylinder; adding a vortex → lifting cylinder.
- Source + vortex at the same point → spiral vortex (bathtub drain if a sink).
Formulas
- Uniform flow:
φ = V∞·x = V∞·r·cos θ,ψ = V∞·y = V∞·r·sin θ— V∞ (m/s). - Source/sink:
φ = (Λ/2π)·ln r,ψ = (Λ/2π)·θ,V_r = Λ/(2πr),V_θ = 0— Λ (m²/s), r (m). - Doublet:
φ = (κ/2π)·cos θ / r,ψ = −(κ/2π)·sin θ / r,V_r = −(κ/2π)·cos θ / r²,V_θ = −(κ/2π)·sin θ / r²— κ (m³/s). - Vortex:
φ = −(Γ/2π)·θ,ψ = (Γ/2π)·ln r,V_r = 0,V_θ = −Γ/(2πr)— Γ (m²/s), clockwise positive. - Rankine half-body: stagnation point at
x_s = −Λ/(2πV∞); body (dividing streamline)ψ = Λ/2; asymptotic total widthh = Λ/V∞. - Bernoulli between any two points:
p₁ − p₂ = ½ρ(V₂² − V₁²)andC_p = 1 − (V/V∞)².
Worked examples
Example 1 (standard). A source of strength Λ = 4π m²/s and a vortex of strength Γ = 8π m²/s (clockwise) are both at the origin in air (ρ = 1.225 kg/m³). Find the velocity at r = 2 m, its direction, and p(r = 4 m) − p(r = 2 m).
V_r = Λ/(2πr) = 4π/(2π × 2) = 1.0 m/s.V_θ = −Γ/(2πr) = −8π/(2π × 2) = −2.0 m/s(clockwise).|V| = √(1² + 2²) = 2.24 m/s, inclined attan⁻¹(2/1) = 63.4°to the radial direction.- At r = 4 m:
V_r = 0.5,V_θ = −1.0, soV² = 1.25 m²/s²; at r = 2 m,V² = 5 m²/s². - The flow is irrotational outside r = 0, so Bernoulli applies between the points:
p₄ − p₂ = ½ρ(V₂² − V₄²) = 0.5 × 1.225 × (5 − 1.25) = 2.30 Pa.
Answer: |V| = 2.24 m/s at 63.4° to the radius (spiralling outward clockwise); p(4 m) − p(2 m) = 2.30 Pa.
Example 2 (GATE level). A uniform stream V∞ = 10 m/s (air, ρ = 1.225 kg/m³) is combined with a source of strength Λ = 6 m²/s at the origin. Find the stagnation point, the asymptotic width of the half-body, and C_p and the gauge pressure p − p∞ on the body directly above the source.
- Stagnation point:
V∞ + Λ/(2πx) = 0 ⇒ x_s = −Λ/(2πV∞) = −6/(2π × 10) = −0.0955 m. - Asymptotic width:
h = Λ/V∞ = 6/10 = 0.6 m(half-width 0.3 m). - Body streamline ψ = Λ/2:
V∞ r sin θ + Λθ/(2π) = Λ/2. At θ = 90°:10r + 6/4 = 3 ⇒ r = 0.15 m(= Λ/(4V∞)). - Velocity there:
u = V∞ + V_r cos 90° = 10 m/s,v = V_r = Λ/(2πr) = 6/(2π × 0.15) = 6.37 m/s(= 2V∞/π). C_p = 1 − (u² + v²)/V∞² = 1 − (1 + 4/π²) = −4/π² = −0.405.p − p∞ = C_p·½ρV∞² = −0.405 × 0.5 × 1.225 × 100 = −24.8 Pa.
Answer: stagnation point 0.0955 m upstream of the source; width 0.6 m; C_p = −0.405, p − p∞ = −24.8 Pa above the source.
Common mistakes
- Using a 3-D point-source formula (V = Q/4πr²) for a 2-D line source; in 2-D, V_r = Λ/(2πr) and Λ is in m²/s.
- Calling the vortex velocity "radial" — it is tangential; a source's velocity is radial.
- Mixing sign conventions: if your text takes Γ positive anticlockwise, V_θ = +Γ/(2πr) and the lift formula carries the corresponding sign.
- Believing the vortex flow is rotational. Only its centre is; everywhere else ω = 0.
- Superposing pressures rather than velocities.
- Forgetting that the singular point must lie inside the body.
For GATE AE
Expect: velocity at a point due to one or more singularities; strength of a source or vortex from a measured velocity; stagnation-point location for half-bodies and ovals; checking which combinations satisfy Laplace's equation; and circulation round a given contour. Learn the φ/ψ table both ways and state the sign convention in your working.
Quick check
- A 2-D source gives V_r = 5 m/s at r = 2 m. Find Λ.
- A vortex induces 4 m/s at r = 1 m. Find |Γ|.
- What is the circulation round a circle that does not enclose a point vortex?
- Which combination of elementary flows gives a Rankine half-body?
Answers: 1. Λ = 2πrV_r = 20π ≈ 62.8 m²/s. 2. |Γ| = 2πrV_θ = 8π ≈ 25.1 m²/s. 3. Zero. 4. Uniform flow plus a source.
Interview questions
All Incompressible Aerodynamics interview questionsTry answering each one aloud before you open it.
1.What is a uniform flow in the context of incompressible aerodynamics?Concept
A uniform flow has the same velocity V∞, in magnitude and direction, at every point. For a stream along +x, φ = V∞x and ψ = V∞y, so streamlines are straight horizontal lines and equipotentials vertical lines. It is irrotational and satisfies Laplace's equation, and it is the free stream to which sources, doublets and vortices are added to model flow past bodies.
2.Explain the concept of a source and a sink in fluid dynamics.Concept
A 2-D source is a line from which fluid emerges radially at a volume rate Λ per unit depth (m²/s); a sink is the same with Λ negative. The velocity is purely radial, V_r = Λ/(2πr), with φ = (Λ/2π) ln r and ψ = (Λ/2π)θ, so streamlines are radial lines and equipotentials circles. The flow is irrotational and satisfies continuity everywhere except the singular point r = 0, which must lie inside the body being modelled.
3.What is a doublet in the study of elementary flows?Concept
A doublet is a combination of a source and a sink of equal strength placed infinitesimally close to each other. It is used to model flow patterns around objects, such as the flow around a cylinder, by creating a flow field that simulates the effect of an object in a fluid.
4.Describe a vortex in the context of incompressible aerodynamics.Concept
A point (line) vortex has purely circumferential velocity V_θ = Γ/(2πr) in magnitude, with streamlines that are concentric circles. Surprisingly it is irrotational everywhere except at the centre: all its vorticity is concentrated at r = 0, so the circulation is Γ round any curve enclosing the centre and zero otherwise. Bound vortices model the circulation that produces lift on an airfoil, and real vortices have a finite viscous core.
5.Why is the concept of a doublet used in modeling the flow around a cylinder?Application
The concept of a doublet is used to model the flow around a cylinder because it can simulate the effect of an impermeable boundary in a fluid. By placing a doublet at the center of the cylinder, the resulting flow pattern mimics the flow around the cylinder, allowing for the analysis of pressure distribution and lift forces.
6.What happens to the flow field if a source and a sink of equal strength are placed close together?Application
At finite spacing the fluid leaving the source travels along circular-arc streamlines into the sink. In the limit of zero spacing with the product κ = lΛ held constant the pair becomes a doublet, whose streamlines are circles through the doublet point tangent to its axis. Adding a uniform stream turns this into flow past a body: a source-sink pair gives a Rankine oval, and a doublet gives a circular cylinder.
7.How does a vortex affect the lift on an airfoil?Application
A vortex affects the lift on an airfoil by altering the pressure distribution around it. The circulation of the vortex can increase the velocity over the upper surface of the airfoil, reducing pressure and thereby increasing lift according to Bernoulli's principle. This is a key concept in understanding how wings generate lift.
8.Calculate the velocity potential for a uniform flow with velocity U = 10 m/s in the x-direction.Numerical
The velocity potential φ for a uniform flow in the x-direction is given by φ = Ux. For U = 10 m/s, the velocity potential is φ = 10x. This represents the potential function for the flow field, where the gradient gives the velocity vector.
9.Determine the stream function for a source of strength Q = 5 m²/s located at the origin.Numerical
The stream function ψ for a source located at the origin is given by ψ = (Q/2π)θ, where θ is the angle in polar coordinates. For Q = 5 m²/s, the stream function is ψ = (5/2π)θ. This function describes the flow lines around the source.
10.Explain how the superposition principle is applied in elementary flows.Concept
The superposition principle in elementary flows allows for the combination of different flow patterns, such as uniform flow, sources, sinks, doublets, and vortices, to model complex flow fields. By adding the velocity potentials or stream functions of individual flows, a composite flow field can be constructed, which is useful in solving problems involving multiple flow interactions.
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