Landing performance

Phases and reference speeds of landing, approach and flare geometry, the braking-roll equation with spoilers and reverse thrust, and what drives landing distance.

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Why it matters

An aircraft that can take off from a runway must also be able to land on it at its landing weight, on a wet day, with a tailwind component, and still stop with margin. Landing overruns are among the most common serious accidents, and certified landing distances carry large safety factors for exactly that reason. Landing analysis decides flap and spoiler design, brake and reverser sizing, and the runway an operator can use.

Key ideas

Phases of landing.

  1. Approach from the screen height (15 m / 50 ft) along a steady glide path, typically 3°, at the approach speed V_a ≈ 1.3·V_stall (V_REF for transports).
  2. Flare: a curved path that reduces the descent rate before touchdown; the mean flare speed is about 1.23·V_stall and the load factor during the flare is about n = 1.2.
  3. Touchdown at V_TD ≈ 1.15·V_stall.
  4. Free roll for 1–3 s while spoilers deploy, the nose comes down and brakes are applied.
  5. Braking roll to rest. Landing distance = approach + flare + free roll + braking roll.

Stall speed in landing configuration. V_stall = √(2W/(ρ·S·C_L,max)) with full landing flaps (C_L,max typically 2.2–3.0 for transports). Landing weight is less than takeoff weight because fuel has been burnt.

Approach and flare geometry. In the flare the aircraft follows a circular arc of radius R = V_f²/(g·(n − 1)). For an approach angle θ_a, the flare starts at height h_f = R·(1 − cos θ_a) and covers horizontal distance s_f = R·sin θ_a. The straight approach from the screen height covers s_a = (h_screen − h_f)/tan θ_a.

Braking roll equation. After touchdown thrust is at idle or in reverse: (W/g)·dV/dt = −[T_rev + D + μ_r·(W − L)]. μ_r is the effective braking coefficient — about 0.4–0.5 on a dry runway with good anti-skid, 0.2–0.3 wet, and below 0.1 on ice (take values from your data book). Spoilers destroy lift so that L ≈ 0 and the full weight presses on the braked wheels; they also add drag. Writing the deceleration as A + B·V², with

  • A = g·(T_rev/W + μ_r)
  • B = (g/W)·½ρS·(C_D,g − μ_r·C_L,g) the braking distance from V_TD to rest is s_b = (1/(2B))·ln(1 + B·V_TD²/A). If aerodynamic forces are neglected, B → 0 and s_b = V_TD²/(2·A), i.e. V_TD²/(2·μ_r·g) without reverse thrust.

What matters most. Since V_TD² ∝ W/(ρ·C_L,max), the braking roll grows with weight, falls with density and falls with better flaps. Reverse thrust and spoilers matter most at high speed, where they supplement brakes; wheel brakes dominate at low speed. A headwind reduces the ground speed at touchdown (V_TD − V_w), and with roughly V² dependence even a modest headwind cuts the roll noticeably. Downhill slope, wet or contaminated runways and tailwind all increase the distance.

Approach speed sensitivity. Because distance scales with V², a 10 % excess approach speed lengthens the braking roll by about 21 %. Pilots are trained to fly V_REF accurately for this reason.

Regulatory margins. Certified (demonstrated) landing distances are factored — for transports the required field length is the demonstrated distance divided by 0.6 on a dry runway, with a further increase for wet runways (see the applicable regulations).

Formulas

V_stall = √(2W / (ρ·S·C_L,max)), V_a ≈ 1.3·V_stall, V_f ≈ 1.23·V_stall, V_TD ≈ 1.15·V_stall

R = V_f² / (g·(n − 1)), h_f = R·(1 − cos θ_a), s_f = R·sin θ_a

s_a = (h_screen − h_f) / tan θ_a

s_fr = N·V_TD (free roll for N seconds)

(W/g)·dV/dt = −[T_rev + D + μ_r·(W − L)]

s_b = (1/(2B))·ln(1 + B·V_TD²/A), A = g·(T_rev/W + μ_r), B = (g/W)·½·ρ·S·(C_D,g − μ_r·C_L,g)

s_b = V_TD² / (2·μ_r·g) (aerodynamic forces and reverse thrust neglected)

Symbols: W landing weight (N); ρ density (kg/m³); S wing area (m²); C_L,max landing-configuration maximum lift coefficient; V speeds (m/s); n flare load factor; R flare radius (m); θ_a approach angle; h_screen screen height (15 m); h_f flare height (m); s_a, s_f, s_fr, s_b approach, flare, free-roll and braking distances (m); N free-roll time (s); T_rev reverse thrust (N); μ_r effective braking coefficient; C_L,g, C_D,g lift and drag coefficients during the roll; g = 9.81 m/s².

Worked examples

Example 1 (standard): braking roll with brakes only. Given: landing weight W = 500 kN, S = 120 m², C_L,max = 2.4, sea level (ρ = 1.225 kg/m³), V_TD = 1.15·V_stall, μ_r = 0.4. Neglect aerodynamic forces and reverse thrust; free roll 2 s.

  1. V_stall = √(2W/(ρSC_L,max)) = √(1 000 000/352.8) = 53.24 m/s; V_TD = 1.15 × 53.24 = 61.23 m/s.
  2. s_b = V_TD²/(2μ_r g) = 3748.6/(2 × 0.4 × 9.81) = 477.6 m.
  3. Free roll = 2 × 61.23 = 122.5 m, so ground distance = 600 m.

Example 2 (GATE level): full landing distance with spoilers and reversers. Given: same aircraft; approach angle 3°, flare speed 1.23·V_stall with n = 1.2, screen height 15 m. In the braking roll: C_L,g = 0.1 (spoilers out), C_D,g = 0.12, μ_r = 0.3, reverse thrust 50 kN constant; free roll 2 s.

  1. Flare: V_f = 1.23 × 53.24 = 65.48 m/s; R = V_f²/(g(n − 1)) = 4288.3/(9.81 × 0.2) = 2186 m.
  2. h_f = R(1 − cos 3°) = 2186 × 0.00137 = 2.99 m; s_f = R·sin 3° = 114.4 m.
  3. Approach: s_a = (15 − 2.99)/tan 3° = 12.01/0.05241 = 229.1 m.
  4. Braking: A = g(T_rev/W + μ_r) = 9.81 × (0.1 + 0.3) = 3.924 m/s²; B = (g/W)·½ρS(C_D,g − μ_rC_L,g) = (9.81/500 000) × 73.5 × 0.09 = 1.298 × 10⁻⁴ m⁻¹.
  5. s_b = (1/(2B))·ln(1 + B·V_TD²/A) = 3852.6 × ln(1 + 0.12398) = 3852.6 × 0.11688 = 450.3 m.
  6. Total = 229.1 + 114.4 + 122.5 + 450.3 = 916 m from the screen to rest.

Common mistakes

  • Using takeoff weight or cruise-configuration C_L,max for landing.
  • Forgetting the free-roll distance, which can be 100–150 m for a transport.
  • Leaving L = W in the friction term after spoilers deploy, or forgetting that lift reduces braking effectiveness when spoilers are not used.
  • Applying the dry-runway braking coefficient to a wet runway.
  • Treating a 10 % speed excess as a 10 % distance increase; it is about 21 %.

For GATE AE

Expect braking-roll numericals with s = V²/(2a) and the A + BV² integration, approach and flare geometry with the circular-arc model, effects of weight, density, headwind and approach-speed error on landing distance, and conceptual questions on spoilers, reverse thrust and braking coefficients. Practise splitting the landing distance into its segments and checking which one dominates.

Quick check

  1. How does braking roll scale with touchdown speed?
  2. Why are spoilers deployed immediately after touchdown?
  3. What is the flare radius for V_f = 60 m/s and n = 1.2?
  4. Touchdown speed 60 m/s, headwind 6 m/s: by what factor does the simple braking roll fall?

Answers: 1. As V_TD². 2. To dump lift so the wheels carry the weight and brakes work, and to add drag. 3. 3600/(9.81 × 0.2) = 1835 m. 4. (54/60)² = 0.81.

Try answering each one aloud before you open it.

  1. 1.What is landing performance in the context of aircraft operations?Concept

    Landing performance refers to the ability of an aircraft to safely land within a specified distance on a runway. It involves assessing factors such as approach speed, landing distance, braking efficiency, and environmental conditions to ensure the aircraft can stop safely after touchdown.

  2. 2.Explain the factors that affect the landing distance of an aircraft.Concept

    The landing distance of an aircraft is affected by several factors including aircraft weight, wind conditions, runway slope, runway surface condition, and the effectiveness of the braking system. Heavier aircraft require longer distances to stop, while headwinds can reduce landing distance. A wet or icy runway can increase the distance needed to stop.

  3. 3.Why is it important to consider runway slope when calculating landing performance?Application

    Runway slope affects the landing performance because an uphill slope can help slow down the aircraft, reducing the landing distance, while a downhill slope can increase the landing distance by making it harder to decelerate. Accurate calculations ensure safety and compliance with performance regulations.

  4. 4.What happens if an aircraft lands with a tailwind instead of a headwind?Application

    Landing with a tailwind increases the landing distance because the aircraft's ground speed is higher upon touchdown. This requires more runway length to decelerate and stop safely. It can also affect the aircraft's stability and control during landing.

  5. 5.How does aircraft weight influence landing performance?Application

    Aircraft weight significantly influences landing performance. A heavier aircraft requires more lift to stay airborne, which translates to a higher approach speed and consequently a longer landing distance. Proper weight management is crucial for ensuring safe landing operations.

  6. 6.Explain the role of reverse thrust in landing performance.Concept

    Reverse thrust is used to help slow down the aircraft after landing by redirecting engine thrust forward. It reduces the reliance on wheel brakes and can significantly decrease the landing distance, especially on wet or slippery runways.

  7. 7.What is the impact of a wet runway on landing performance?Application

    A wet runway can increase the landing distance due to reduced friction between the aircraft's tires and the runway surface. This can lead to hydroplaning, where the tires lose contact with the runway, making braking less effective and requiring more distance to stop.

  8. 8.Calculate the landing distance required for an aircraft with a landing speed of 70 m/s, assuming a deceleration rate of 3 m/s².Numerical

    To calculate the landing distance, use the formula: distance = (speed²) / (2 * deceleration). Here, distance = (70²) / (2 * 3) = 4900 / 6 = 816.67 meters. Therefore, the landing distance required is approximately 817 meters.

  9. 9.If an aircraft's touchdown speed is reduced by 10 %, how does this affect the landing ground roll?Application

    For a given deceleration the braking distance is s = V²/(2a), so it scales with the square of touchdown speed. A 10 % reduction gives 0.9² = 0.81, i.e. about a 19 % shorter roll; conversely a 10 % excess speed gives about 21 % more. This is why accurate speed control on approach (flying V_REF) matters so much, and why high-lift devices that cut stall speed shorten landings.

  10. 10.An aircraft lands with a speed of 60 m/s and comes to a stop in 30 seconds. What is the average deceleration?Numerical

    The average deceleration can be calculated using the formula: deceleration = (final speed - initial speed) / time. Here, deceleration = (0 - 60) / 30 = -60 / 30 = -2 m/s². The negative sign indicates deceleration.

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