Probability & Statistics
Probability and statistics underpin algorithm analysis, machine learning, and network traffic models. GATE tests Bayes' theorem, distributions, expected value, and basic statistical measures.
Key Points
- ·P(A) ∈ [0,1]; P(Ω) = 1; P(A ∪ B) = P(A) + P(B) − P(A∩B)
- ·Conditional probability: P(A|B) = P(A∩B)/P(B)
- ·Bayes' theorem: P(A|B) = P(B|A)·P(A) / P(B)
- ·Independent: P(A∩B) = P(A)P(B). Mutually exclusive: P(A∩B) = 0
- ·Binomial B(n,p): E[X]=np, Var=np(1-p)
- ·Poisson(λ): E[X]=Var(X)=λ; models rare events
- ·Geometric: memoryless property; Exponential: continuous memoryless
What is Probability?
Flip a fair coin. What is the chance of heads? 1/2. Probability measures how likely an event is, from 0 (impossible) to 1 (certain).
Sample space Ω = set of all possible outcomes. Event A = a subset of outcomes we care about.
Roll a die: Ω = {1, 2, 3, 4, 5, 6}
Event A = "roll an even number" = {2, 4, 6}
P(A) = 3/6 = 1/2
Basic Rules
P(Aᶜ) = 1 − P(A) [complement]
P(A ∪ B) = P(A) + P(B) − P(A ∩ B) [inclusion-exclusion]
P(A ∪ B) = P(A) + P(B) only if A, B are mutually exclusive
Conditional Probability — Updating Beliefs
"Given that it's cloudy, what's the probability of rain?"
P(rain | cloudy) = P(rain AND cloudy) / P(cloudy)
General formula:
P(A | B) = P(A ∩ B) / P(B) [requires P(B) > 0]
Independence vs Mutually Exclusive
These are completely different concepts that confuse many students:
| Concept | Definition | Real-world analogy |
|---|---|---|
| Independent | P(A∩B) = P(A)·P(B) | Two separate coin flips |
| Mutually exclusive | P(A∩B) = 0 | "heads" and "tails" on same flip |
Mutually exclusive events (if P(A)>0 and P(B)>0) are actually dependent — if A happened, B definitely didn't!
Bayes' Theorem — Reversing Conditional Probability
You know P(B|A), but want P(A|B). Bayes flips it:
P(A|B) = P(B|A) · P(A) / P(B)
The medical test example (classic GATE scenario):
- Disease prevalence: P(D) = 0.01 (1% of population)
- Test sensitivity: P(+|D) = 0.95 (if you have disease, 95% chance test is positive)
- False positive rate: P(+|no D) = 0.10
What is P(D|+)? (Probability you actually have disease given positive test?)
P(+) = P(+|D)·P(D) + P(+|no D)·P(no D)
= 0.95×0.01 + 0.10×0.99
= 0.0095 + 0.099 = 0.1085
P(D|+) = P(+|D)·P(D) / P(+) = 0.0095 / 0.1085 ≈ 0.088
Surprising result: Even with 95% sensitivity, a positive test only means ~9% chance of disease! This is because the disease is rare.
Discrete Random Variables and Distributions
Binomial Distribution B(n, p)
Scenario: Flip a biased coin (P(heads)=p) exactly n times. X = number of heads.
P(X = k) = C(n,k) · pᵏ · (1−p)ⁿ⁻ᵏ
E[X] = np
Var(X) = np(1−p)
Example: 10 questions, each answered randomly (p=0.25). Expected correct = 10 × 0.25 = 2.5.
Geometric Distribution G(p)
Scenario: Keep flipping until first head. X = number of flips needed.
P(X = k) = (1−p)ᵏ⁻¹ · p [k = 1, 2, 3, ...]
E[X] = 1/p
Memoryless: P(X > s+t | X > s) = P(X > t)
Poisson Distribution Poisson(λ)
Scenario: Rare events in a fixed interval. Customers arriving, typos per page, cosmic rays hitting a detector.
P(X = k) = e⁻λ · λᵏ / k!
E[X] = Var(X) = λ ← mean equals variance — unique to Poisson!
When to use Poisson: n is very large, p is very small, np = λ is moderate.
Continuous Distributions
Normal Distribution N(μ, σ²)
The famous bell curve. Symmetric around mean μ.
68-95-99.7 Rule:
P(μ−σ < X < μ+σ) ≈ 68%
P(μ−2σ < X < μ+2σ) ≈ 95%
P(μ−3σ < X < μ+3σ) ≈ 99.7%
Standardise: Z = (X − μ)/σ converts any normal to standard normal N(0,1).
Exponential Distribution Exp(λ)
Models time between events in a Poisson process (time until next customer, equipment lifetime).
E[X] = 1/λ, Var(X) = 1/λ²
Memoryless: P(X > s+t | X > s) = P(X > t)
Expected Value and Variance
Expected value = weighted average of all outcomes:
E[X] = Σ x · P(X = x) [discrete]
Example: Fair die: E[X] = 1·(1/6) + 2·(1/6) + ... + 6·(1/6) = 21/6 = 3.5
Variance = expected squared deviation from mean:
Var(X) = E[X²] − (E[X])² ← shortcut formula
Key linearity rules:
E[aX + b] = a·E[X] + b
Var(aX + b) = a²·Var(X)
E[X + Y] = E[X] + E[Y] [always true]
Var(X + Y) = Var(X) + Var(Y) [only if X, Y are independent]
Quick Check
Q1. P(A) = 0.4, P(B) = 0.3, P(A∩B) = 0.1. Find P(A|B).
Answer: P(A|B) = P(A∩B)/P(B) = 0.1/0.3 = 1/3 ≈ 0.33.
Q2. X ~ Poisson(4). What is E[X] and Var(X)?
Answer: Both equal 4 (Poisson mean = variance = λ).
Q3. X ~ Binomial(20, 0.3). Find E[X] and Var(X).
Answer: E[X] = 20×0.3 = 6. Var(X) = 20×0.3×0.7 = 4.2.
Key Formulas
- Bayes' theorem: P(A|B) = P(B|A)·P(A) / P(B)
- Binomial: E[X]=np, Var(X)=np(1-p)
- Poisson: E[X] = Var(X) = λ
- Variance shortcut: Var(X) = E[X²] − (E[X])²
GATE Exam Tips
- ★Bayes' theorem: the rare-disease paradox is a classic — low prior probability dominates
- ★Independent ≠ mutually exclusive. Know both definitions and the difference.
- ★Poisson: mean equals variance = λ. If a problem says mean=variance, think Poisson.
- ★Geometric is memoryless (discrete); Exponential is memoryless (continuous) — both appear in GATE
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